nitrit de liti y nitrat de berili

nitrit de liti:


2·H_{2}N(OH) + Li_{2} + e^{-} ==> 2·H_{2}NLi + H_{2}O_{2}
2·H_{2}NLi + H_{2}O_{2} + e^{+} ==> 2·H_{2}N(OH) + Li_{2}


Entalpia de reacción:
[ 2·H_{2}N(OH) ] = 10
[ Li_{2} ] = 2
[ 2·H_{2}NLi ] = 8
[ H_{2}O_{2} ] = 4


10+2 = 8+4 = 12


nitrat de Berili:


2·HN(OH)_{2} + Be_{2} + e^{-} ==> 2·HNBe + 2·H_{2}O_{2}
2·HNBe + 2·H_{2}O_{2} + e^{+} ==> 2·HN(OH)_{2} + Be_{2}


Entalpia de reacción:
[ 2·HN(OH)_{2} ] = 14
[ Be_{2} ] = 4
[ 2·HNBe ] = 10
[ 2·H_{2}O_{2} ] = 8


14+4 = 10+8 = 18