bi-metano octogonal combustión

Oct[C_{8}]H_{8} + 4·O_{2} + e^{+} ==> 4·C_{2}O_{2} + 4·H_{2}


4·C_{2}O_{2} + 4·H_{2} + e^{-} ==> Oct[C_{8}]H_{8} + 4·O_{2}


Entalpia de reacción:
[ Oct[C_{8}]H_{8} ] = 40
[ 4·O_{2} ] = 16


[ 4·C_{2}O_{2} ] = 48
[ 4·H_{2} ] = 8


40+16 = 48+8 = 56