[ n // k_{1}+k_{2}+k_{3} = n ] = ( n!/(k_{1}!·k_{2}!k_{3}!) )
(x+y+z)^{2} = x^{2}+y^{2}+z^{2}+2xy+2yz+2zx
(x+y+z)^{3} = ...
... x^{3}+y^{3}+z^{3}+3x^{2}y+3y^{2}x+3x^{2}z+3z^{2}x+3y^{2}z+3z^{2}y+6xyz
f(k_{1},k_{2}) = [ n // k_{1}+k_{2} = n ]·2^{(-n)}
sum[ f(k_{1},k_{2}) ] = 1
f(k_{1},k_{2},k_{3}) = [ n // k_{1}+k_{2}+k_{3} = n ]·3^{(-n)}
sum[ f(k_{1},k_{2},k_{3}) ] = 1
ae^{x}+be^{y} = e^{ ( ln(a)+x ) [+] ( ln(b)+y ) }
ae^{x}+be^{x} = e^{ ( ln(a)+x ) [+] ( ln(b)+x ) } = e^{( ln(a) [+] ln(b) )+x} = (a+b)·e^{x}
(a+b)·e^{x} = 1
x = (-1)·ln(a+b) = (-1)·( ln(a) [+] ln(b) )
(a+b)·e^{x} = c
x = ln(c)+(-1)·ln(a+b) = ln(c)+(-1)·( ln(a) [+] ln(b) )
ln(16) = ln(8+8) = 3·ln(2) [+] 3·ln(2) = ...
... 3·ln(2)+( 0 [+] 0 ) = 3·ln(2)+( ln(1) [+] ln(1) ) = 3·ln(2)+ln(1+1) = 4·ln(2) = ln(2^{4})
ln(30) = ln(3+27) = ln(3) [+] 3·ln(3) = ...
... ln(3)+( 0 [+] 2·ln(3) ) = ln(3)+( ln(1) [+] ln(9) ) = ln(3)+ln(1+9) = ln(3)+ln(10)
ln(20) = ln(16+4) = 2·ln(4) [+] ln(4) = ...
... ln(4)+( ln(4) [+] 0 ) = ln(4)+( ln(4) [+] ln(1) ) = ln(4)+ln(4+1) = ln(4)+ln(5)
2·( ln(x) [+] ln(y) ) = 2·ln(x+y) = ln( (x+y)^{2} ) = ...
... ln(x^{2}) [+] ln(2xy) [+] ln(y^{2})
( ln(x) [+] ln(y) )+( ln(x) [+] ln(y) ) = ...
... ( ( ln(x) [+] ln(y) )+ln(x) ) [+] ( ( ln(x) [+] ln(y) )+ln(y) )
n·e^{ln(x) [+] ln(y)} = n·e^{ln(x+y)} = nx+ny = ne^{ln(x)}+ne^{ln(y)}
x^{n}+x^{m} = c
x = c^{( 1/( n [+] m ) )}
x^{n}+x^{m} = ( c^{( 1/( n [+] m ) )} )^{n}+( c^{( 1/( n [+] m ) )} )^{m} = ...
... ( c^{( 1/( n [+] m ) )} )^{( n [+] m )} = c^{( ( n [+] m )/( n [+] m ) )} = c
d_{x}[y(x)]^{n}+d_{x}[y(x)]^{m} = d_{x}[f(x)]
x = ( f(x) )^{[o(x)o]( 1/( n [+] m ) )}
ax^{n}+bx^{m} = c
polinomi asociat resoluble:
px^{n}+qx^{m} = c
p = a^{( 1/( ( log_{c}(a)+n ) [+] ( log_{c}(b)+m ) ) )}
q = b^{( 1/( ( log_{c}(a)+n ) [+] ( log_{c}(b)+m ) ) )}
x = c^{( 1/( ( log_{c}(a)+n ) [+] ( log_{c}(b)+m ) ) )}
px^{n}+qx^{m} = ...
... ( c^{( 1/( ( log_{c}(a)+n ) [+] ( log_{c}(b)+m ) ) )} )^{( log_{c}(a)+n )}+...
... ( c^{( 1/( ( log_{c}(a)+n ) [+] ( log_{c}(b)+m ) ) )} )^{( log_{c}(b)+m )} = c
100·x^{100}+1000·x^{48} = 10
polinomi asociat resoluble:
px^{100}+qx^{48} = 10
p = 10^{( 2/( 102 [+] 51 ) )}
q = 10^{( 3/( 102 [+] 51 ) )}
x = 10^{( 1/( 102 [+] 51 ) )}
81·x^{8}+27·x^{3} = 3
polinomi asociat resoluble:
px^{8}+qx^{3} = 3
p = 3^{( 4/( 12 [+] 6 ) )}
q = 3^{( 3/( 12 [+] 6 ) )}
x = 3^{( 1/( 12 [+] 6 ) )}
(-s) < (a_{n+1}+(-1)·a_{n})/(b_{n+1}+(-1)·b_{n})+(-l) < s
(-s) < ( (a_{n+1}+(-1)·a_{n})/b_{n+1} )+(-l)·( (b_{n+1}+(-1)·b_{n})/b_{n+1} ) < s
l = (n+1)
(a_{n+1}/b_{n+1}) = lim[ (1+...(n)...+n+(n+1))/(n+1) ] = (1/2)·(n+2)
(a_{n}/b_{n+1}) = lim[ (1+...(n)...+n)/(n+1) ] = (n/2)
l = (n+1)^{2}
(a_{n+1}/b_{n+1}) = lim[ (1^{2}+...(n)...+n^{2}+(n+1)^{2})/(n+1) ] = ((n/6)+(1/3))·(2n+3)
(a_{n}/b_{n+1}) = lim[ (1^{2}+...(n)...+n^{2})/(n+1) ] = (n/6)·(2n+1)
Derecho a la Vida.
Derecho a la Sanidad.
Derecho a la Muerte.
Derecho a la Autenasia.
La autenasia tiene que ser, de X-eplion-Vega,
porque homosexuales o deficientes,
no son resistentes al X-eplion-Vega.
La autenasia no tiene que ser, de no X-eplion-Vega,
porque heterosexuales y intelectuales,
son resistentes al X-eplion-Vega.
var [o] vando [o] vado
dar [o] dando [o] dado
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