carburo de dos hidrógenos hexagonal

Hex[C_{6}]H_{2} + O_{2} + e^{+} ==> C_{6}O_{2} + H_{2}


C_{6}O_{2} + H_{2} + e^{-} ==> Hex[C_{6}]H_{2} + O_{2}


Entalpia de reacción:
[ Hex[C_{6}]H_{2} ] = 10
[ O_{2} ] = 4


[ C_{6}O_{2} ] = 12
[ H_{2} ] = 2


10+4 = 12+2 = 14