Principio: [ orbital en un cuerpo celeste ]
I_{c}·d_{t}[w]^{2} = pq·k·(1/R)
Ley
Órbita lunar:
B(d_{t}[w]) = qk·(1/r)^{2}·( (1/I_{c})·pq·k·(1/R) )^{(1/2)}
Alunizar:
E(w) = qk·(1/r)^{2}·( (1/I_{c})·pq·k·(1/R) )^{(1/2)}·t
Ley:
x(t) = (1/m)·pqk·(1/r)^{2}·( (1/I_{c})·pq·k·(1/R) )^{(1/2)}·(1/6)·t^{3}+...
... (-1)·( (1/I_{c})·pq·k·(1/R) )^{(1/2)}·ht+h
d_{t}[x] = (1/m)·pqk·(1/r)^{2}·( (1/I_{c})·pq·k·(1/R) )^{(1/2)}·(1/2)·t^{2}+...
... (-1)·( (1/I_{c})·pq·k·(1/R) )^{(1/2)}·h
d_{t}[x(t_{k})] = 0 <==> t_{k} = ( h·( (2m)/(pqk) )·r^{2} )^{(1/2)}
x(t_{k}) = 0 <==> h = ( ( (1/I_{c})·pq·k·(1/R) )·(2/3)·( ( (2m)/(pqk) )·r^{2} ) )^{(-1)}
Teorema:
a·( cos(t) )^{2}+b·( sin(t) )^{2} = R^{2} <==> ( a = R^{2} & b = R^{2} )
Ley:
((mc)/2)·d_{t}[r] = pqk·(1/r) = Potencial[ E_{g}(x,y,z,t) ]
r(t) = ( (4/(mc))·pqk t+(1/2)·R^{2} )^{(1/2)}
((mc)/2)·d_{t}[r] = (-1)·pqk·(1/r) = Potencial[ int[ B_{g}(d_{t}[x],d_{t}[y],d_{t}[z],t) ]d[t] ]
r(t) = ( (-1)·(4/(mc))·pqk t+(1/2)·R^{2} )^{(1/2)}
Ley:
x^{2}+y^{2} = R^{2}
x(t) = ( (4/(mc))·pqk·t+(1/2)·R^{2} )^{(1/2)}
y(t) = ( (-1)·(4/(mc))·pqk·t+(1/2)·R^{2} )^{(1/2)}
Ley:
x^{2}+(-1)·y^{2} = R^{2}
x(t) = ( (4/(mc))·pqk·t+(1/2)·R^{2} )^{(1/2)}
y(t) = ( (4/(mc))·pqk·t+(-1)·(1/2)·R^{2} )^{(1/2)}
Ley:
(m/2)·d_{t}[r]^{2} = pqk·(1/r)
r(t) = ( [( 3·( (1/(2m))·pqk )^{(1/2)}·t+( (1/2)·R^{3} )^{(1/2)} )] )^{(2/3)}
(m/2)·d_{t}[r]^{2} = (-1)·pqk·(1/r)
r(t) = ( [( 3·( (1/(2m))·pqk )^{(1/2)}·it+( (1/2)·R^{3} )^{(1/2)} )] )^{(2/3)}
Ley:
x^{3}+y^{3} = R^{3}
x(t) = ( [( 3·( (1/(2m))·pqk )^{(1/2)}·t+( (1/2)·R^{3} )^{(1/2)} )] )^{(2/3)}
y(t) = ( [( 3·( (1/(2m))·pqk )^{(1/2)}·it+( (1/2)·R^{3} )^{(1/2)} )] )^{(2/3)}
Ley:
x^{3}+(-1)·y^{3} = R^{3}
x(t) = ( [( 3·( (1/(2m))·pqk )^{(1/2)}·t+( (1/2)·R^{3} )^{(1/2)} )] )^{(2/3)}
y(t) = ( [( 3·( (1/(2m))·pqk )^{(1/2)}·t+( (-1)·(1/2)·R^{3} )^{(1/2)} )] )^{(2/3)}
Ley:
((mu)/2)·d_{t}[w] = 2pqk·(1/(dw))^{3} = d_{rrr}^{3}[ pqk·ln(r) ]
w(t) = ( [( 16·(1/(mu))·pqk·(1/d)^{3}·t+(1/2) )] )^{(1/4)}
((mu)/2)·d_{t}[w] = (-2)·pqk·(1/(dw))^{3} = d_{rrr}^{3}[ (-1)·pqk·ln(r) ]
w(t) = ( [( (-16)·(1/(mu))·pqk·(1/d)^{3}·t+(1/2) )] )^{(1/4)}
Ley:
x^{4}+y^{4} = R^{4}
x(t) = R·( 16·(1/(mu))·pqk·(1/d)^{3}·t+(1/2) )^{(1/4)}
y(t) = R·( (-16)·(1/(mu))·pqk·(1/d)^{3}·t+(1/2) )^{(1/4)}
Ley:
x^{4}+(-1)·y^{4} = R^{4}
x(t) = R·( 16·(1/(mu))·pqk·(1/d)^{3}·t+(1/2) )^{(1/4)}
y(t) = R·( 16·(1/(mu))·pqk·(1/d)^{3}·t+(-1)·(1/2) )^{(1/4)}
Ley:
(m/2)·d_{t}[w]^{2} = 2pqk·(1/(dw))^{3} = d_{rrr}^{3}[ pqk·ln(r) ]
w(t) = ( [( 5·( (1/m)·pqk·(1/d)^{3} )^{(1/2)}·t+(1/2)^{(1/2)} )] )^{(2/5)}
(m/2)·d_{t}[w]^{2} = (-2)·pqk·(1/(dw))^{3} = d_{rrr}^{3}[ (-1)·pqk·ln(r) ]
w(t) = ( [( 5·( (1/m)·pqk·(1/d)^{3} )^{(1/2)}·it+(1/2)^{(1/2)} )] )^{(2/5)}
Ley:
x^{5}+y^{5} = R^{5}
x(t) = R·( [( 5·( (1/m)·pqk·(1/d)^{3} )^{(1/2)}·t+(1/2)^{(1/2)} )] )^{(2/5)}
y(t) = R·( [( 5·( (1/m)·pqk·(1/d)^{3} )^{(1/2)}·it+(1/2)^{(1/2)} )] )^{(2/5)}
Ley:
x^{5}+(-1)·y^{5} = R^{5}
x(t) = R·( [( 5·( (1/m)·pqk·(1/d)^{3} )^{(1/2)}·t+(1/2)^{(1/2)} )] )^{(2/5)}
y(t) = R·( [( 5·( (1/m)·pqk·(1/d)^{3} )^{(1/2)}·t+i·(1/2)^{(1/2)} )] )^{(2/5)}
Teorema:
[An][ n = 2m ==> [Ea][Eb][ a = 2p+1 & b = 2q+1 & a € P & b € P & n = a+b ] ]
Demostración:
Sea n = 2m ==>
[Ew][ n = 2w+2 & w = m+(-1) ]
[Ep][Eq][ n = 2p+1+2q+1 & p = w+(-q) ]
Se define a = 2p+1 & b = 2q+1 ==>
n = 2p+1+2q+1 = a+b
22 = 20+2 = 2·10+2 = 2·8+1+2·2+1 = 17+5
22 = 20+2 = 2·10+2 = 2·9+1+2·1+1 = 19+3
Sea f(1) = 0 ==>
a = 2p+1 = 2p+f(1) = 2p+0 = 2p
2 | a
b = 2q+1 = 2q+f(1) = 2q+0 = 2q
2 | b
Sea h(0) = 1 ==> [ por inducción ]
k+1 = k+h(0) = k+0 = k | 2p
a € P
j+1 = j+h(0) = j+0 = j | 2q
b € P
Teorema:
[An][ n = 2m+1 ==> [Ea][Eb][ a = 2p+2 & b = 2q+1 & mcd{a,b} = 1 & n = a+b ] ]
Demostración:
Sea n = 2m+1 ==>
[Ew][ n = 2w+2+1 & w = m+(-1) ]
[Ep][Eq][ n = 2p+2+2q+1 & p = w+(-q) ]
Se define a = 2p+2 & b = 2q+1 ==>
n = 2p+2+2q+1 = a+b
15 = 12+3 = 2·6+3 = 2·3+2+2·3+1 = 8+7
15 = 12+3 = 2·6+3 = 2·1+2+2·5+1 = 4+11
Falsus Algebratorum:
a = 2p+2 = 2p+(3/2)+(1/2) = 2p+(3/2)+(-1)·(1/2) = 2p+1
Sea f(1) = 0 ==>
a = 2p+1 = 2p+f(1) = 2p+0 = 2p
2 | a
b = 2q+1 = 2q+f(1) = 2q+0 = 2q
2 | b
2 | mcd{a,b}
[Ej][ j | mcd{a,b} & j != 1 ]
[Aj][ j | mcd{a,b} ==> j = 1 ]
Ley:
Viajar a la Luna:
qE(x+(-y)) = F
qE(x) = F+qE(y)
Si F = 0 ==> qE(x) = qE(y)
Orbitar en la Luna:
int[ qB(d_{t}[x]+(-1)·d_{t}[y]) ]d[t] = (-F)
int[ qB(d_{t}[x]) ]d[t] = (-F)+int[ qB(d_{t}[y]) ]d[t]
Si (-F) = (-0) ==> int[ qB(d_{t}[x]) ]d[t] = int[ qB(d_{t}[y]) ]d[t]
Ley:
Corriente de fase eléctrica:
L·d_{tt}^{2}[q] = R·d_{t}[q]
q(t) = qe^{(R/L)·t}+q
Corriente de fase magnética:
L·d_{tt}^{2}[p] = (-R)·d_{t}[p]
p(t) = pe^{(-1)·(R/L)·t}+(-p)
q(t) [o] p(t) = 0
Ley:
L·d_{tt}^{2}[q] = C·q(t)
Corriente de fase eléctrica:
q(t) = q·( sinh( (C/L)^{(1/2)}·t )+cosh( (C/L)^{(1/2)}·t ) )
Corriente de fase magnética
p(t) = p·( cosh( (C/L)^{(1/2)}·t )+(-1)·sinh( (C/L)^{(1/2)}·t ) )
q(t) [o] p(t) = 0
Ley:
L·d_{tt}^{2}[p] = (-C)·p(t)
Corriente de fase eléctrica:
q(t) = q·( i·sin( (C/L)^{(1/2)}·t )+cos( (C/L)^{(1/2)}·t ) )
Corriente de fase magnética:
p(t) = p·( cos( (C/L)^{(1/2)}·t )+(-i)·sin( (C/L)^{(1/2)}·t ) )
q(t) [o] p(t) = 0
Principio:
T(n) >] T(n+(-1)) por fisión nuclear
Ley: [ de motor de fisión nuclear quemando uranio ]
T·d_{t}[q] = pW
q(t) = ( (pW)/T )·t
Ley: [ de motor de fisión nuclear poligonal híper-espacial quemando uranio ]
T·d_{t}[q] = Wi·q(t)
q(t) = qe^{(W/T)·it}
Ley: [ de cinemática del viaje a la Luna ]
0 = (-1)·(1/2)·g·(12h)^{2}+40,000·(km/h)·12h+(1/4)·384,000·km
g = (1/12h)^{2}·2·( 40,000·(km/h)·12h+96,000km ) = 8,000·( km/h^{2} )
T_{k} = 28h+48·min
192,000km = 40,000·(km/h)·4.8h = 40,000·(km/h)·( 4h+48min )
(8/10)·60 = (4/5)·60 = 4·12 = 48min
Ley: [ de cinemática del viaje a la Luna ]
0 = (-1)·(1/2)·g·(6h)^{2}+20,000·(km/h)·6h+(1/4)·384,000·km
g = (1/6h)^{2}·2·( 20,000·(km/h)·6h+96,000km ) = 12,000·( km/h^{2} )
T_{k} = 21h+36·min
192,000km = 20,000·(km/h)·9.6h = 20,000·(km/h)·( 9h+36min )
(6/10)·60 = (3/5)·60 = 3·12 = 36min
Ley: [ de barras de regulación de campo eléctrico en la fisión nuclear ]
Sea q(t) = ( (pW)/T )·t ==>
[Et_{0}][ (p/m)·E(z)+(-g) = (p/m)·q(t)·k·(1/r)^{3}·( q( t_{0} )/(a·q(t)) )+(-g) = 8,000·( km/h^{2} ) ]
[Et_{0}][ (p/m)·E(z)+g = (p/m)·q(t)·k·(1/r)^{3}·( q( t_{0} )/(a·q(t)) )+g = 8,000·( km/h^{2} ) ]
Ley: [ de barras de regulación de campo eléctrico en la fisión nuclear ]
Sea q(t) = pe^{(W/T)·it} ==>
[Et_{0}][ (p/m)·E(z) = (p/m)·q(t)·k·(1/r)^{3}·( q( n·pi·t_{0} )/(a·q(t)) ) = 8,000·( km/h^{2} ) ]
Supongo que los fallos en el Artemis II,
dicen que se va a trempar la nave real,
por fallos en los aseos y en el pozo de Jakob,
que dice que se va a trempar el cohete.
Teorema:
[u+v] = [u]+[v]
[a·v] = a·[v]
Demostración:
Sea [u] = (1/2)·F+u & [v] = (1/2)·F+v ==>
[u]+[v] = F+(u+v) = [u+v]
Sea [v] = (1/a)·F+v ==>
a·[v] = F+a·v = [a·v]
Teorema:
[ sum[k = 1]-[n][ a_{k}·v_{k} ] ] = sum[k = 1]-[n][ a_{k}·[v_{k}] ]
Teorema:
Sea F = k·< a,b > ==>
[< x,y >] = [< a,b >]+(x+(-a))·[< 1,0 >]+(y+(-b))·[< 0,1 >]
[< a,b >] = [< a,b >]+[< 0,0 >]
Demostración:
(a+(-a))·[< 1,0 >]+(b+(-b))·[< 0,1 >] = 0·[< 1,0 >]+0·[< 0,1 >] = [< 0,0^{2} >]+[< 0^{2},0 >] = ...
... [< 0+0^{2},0^{2}+0 >] = [< 0,0 >]
Ley: [ de váter espacial ]
m·d_{tt}^{2}[z] = F+(-1)·d_{xyz}^{3}[Q(x,y,z)]·Vg
Si F > d_{xyz}^{3}[Q(x,y,z)]·Vg ==> ...
... Hay ascenso del oxígeno por el filtro comprimiendo,
después del aspirador de campo circular ortogonal central de doble opuestos.
Si F < d_{xyz}^{3}[Q(x,y,z)]·Vg ==> ...
... No hay ascenso de las heces por el filtro comprimiendo,
después del aspirador de campo circular ortogonal central de doble opuestos.
Ley: [ de campo circular ortogonal central ]
z = ( z^{2}+(ir)^{2} )^{(1/2)} <==> r = 0 estando el campo en el eje central.
E(z) = ...
... int[z = 0]-[( z^{2}+(ir)^{2} )^{(1/2)}][ qk·(1/(2pi·r))^{3}·z·( z^{2}+r^{2} )^{(-1)·(1/2)} ]d[z] = ...
... qk·(1/(2pi·r))^{3}·z+(-1)·qk·(1/(2pi·r))^{3}·r
Ley: [ del aspirador de campo circular ortogonal central de doble opuestos ]
m·d_{tt}^{2}[z] = (-p)·E(z)
z(t) = ire^{( (1/m)·(pqk)·(1/(2pi·r))^{3} )^{(1/2)}·it}+r
m·d_{tt}^{2}[z] = pE(z)
z(t) = ire^{( (1/m)·(pqk)·(1/(2pi·r))^{3} )^{(1/2)}·t}+r
Tenemos faro inter-plexo electro-magnético y aun no vemos otros mundos,
no hay faro inter-plexo gravito-magnético,
y aun no sabemos como han encontrado la trayectoria a nuestro sistema estelar,
y aun no han resuelto el váter sin gravedad los alienígenas.
La cienciología es dudosa de creer porque no resuelve estos problemas.
Ley: [ de entrada cúbica en órbita ]
(m/2)·d_{t}[r]^{2} = pqk·(1/r)
r(t) = ( 3·( (1/(2m))·pqk )^{(1/2)}·t )^{(2/3)} = ( 9·( (1/(2m))·pqk )·t^{2} )^{(1/3)}
Sea t^{2} = ((2x)/g) ==>
r(x) = ( 9·( (1/(2m))·pqk )·((2x)/g) )^{(1/3)}
Activando el magnetismo gravitatorio te mantienes en órbita,
porque la Luna no gira como la Tierra.
Ley: [ de cohete polinómico entero ]
m·d_{tt}^{2}[z] = F+(-1)·( 1+(-1)·(ut) )^{n}·qg+(-1)·qg
d_{t}[z(1/u)] = (1/m)·( F+(-1)·qg )·(1/u)
Ley: [ de cohete polinómico racional ]
m·d_{tt}^{2}[z] = F+(-1)·( 1+(-1)·(ut)^{n} )·qg+(-1)·qg
d_{t}[z(1/u)] = (1/m)·( F+(1/(n+1))·qg )·(1/u)
Ley: [ de un cohete logarítmico con medio peso de nave ]
m·d_{tt}^{2}[z] = F+(-1)·( 1/(1+(ut)) )·qg
d_{t}[z(1/u)] = (1/m)·( F+(-1)·ln(2)·qg )·(1/u)
Ley: [ de un cohete trigonométrico con medio peso de nave ]
m·d_{tt}^{2}[z] = F+(-1)·( 1/(1+(ut)^{2}) )·qg
d_{t}[z(1/u)] = (1/m)·( F+(-1)·(pi/4)·qg )·(1/u)
Encuentran interesante para joder,
a los hombres que no cumplimos Hobbes,
encontrando interesante su destrucción y su condenación.
Un país moderno no glorificado como España no tiene sentido joder-lo,
y no es interesante porque no cumple ningún español moderno Hobbes.
Ley: [ de la cienciología inversa ]
Los alienígenas no han construido nada en el antiguo Egipto
Deducción:
Los alienígenas llevan al psiquiatra,
a Akenatón que soy yo y a Tutankamón que es mi sobrino,
y se duda de la construcción de algo en el antiguo Egipto.