d_{t}[x] = (a/b)·x(x+(-b))
( ( 1/(x+(-b)) )+(-1)·(1/x) )·d_{t}[x] = a
ln(x+(-b))+(-1)·ln(x) = at
(1+(-1)(b/x)) = e^{at}
(b/x) = 1+(-1)·e^{at}
x(t) = ( b/(1+(-1)·e^{at}) )
d_{t}[x] = (ba)·( e^{at}/(1+(-1)·e^{at})^{2} )
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