B(r) = (1/10pi)·(4pi)·( p·r^{2}+(-1)·m·(1/3)·r^{3} )
d_{x}[B(r)] = 2p·r+(-1)·m·r^{2}
mr = 2p
r = ( (2p)/m )
B( (2p)/m ) = (4pi)( (2/3)(p^{3}/m^{2}) )
pelota de tenis:
p=3 & m=2
B(3) = (1/10pi)·(18pi) = 1.8€
B(r) = (1/10pi)·( F(r)+(-1)·V(r) )
(1/10pi)·F(3) = 2.7€
(1/10pi)·V(3) = 0.9€
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