química: carbur de nitrogen

2·C_{2} + 2·N_{2} + e^{-}  ==> ( =N-C≡C-N= ) + ( =C=N-N=C= )


( =N-C≡C-N= ) + ( =C=N-N=C= ) + e^{+} ==> 2·C_{2} + 2·N_{2}


entalpia de reacció:
[ 2·C_{2} ] = 16
[ 2·N_{2} ] = 12


[ ( =N-C≡C-N= ) ] = 14
[ ( =C=N-N=C= ) ] = 14


16+12 = 14+14 = 28