analisis funcional formes integrals

∫ [0-->1]-[ ( (-1)·( k/a )·x+( (2k)/b ) ) [o] (ax+b) ] d[x] = k


∫ [0-->1]-[ ( (-1)·( k/a )·e^{x}+( k/b )·e^{2} ) [o] (a·e^{x}+b) ] d[x] = k


∫ [0-->1]-[ ( ( (12k)/(7a) )·( 1/(x+1)^{2} )+( k/b )·( 1/(x+1) ) ) [o] ...
... ( a·( 1/(x+1)^{2} )+b·( 1/(x+1) ) ) ] d[x] = k