Si a_{n+m} = a_{n}+a_{m} ==> (a_{n}/n) = a_{1}
a_{n} = a_{1+...(n)...+1} = n·a_{1}
Si ( a_{n+m} = a_{n}+a_{m} & a_{1} >] 0 ) ==> a_{n} és creishent
Si ( a_{n+m} = a_{n}+a_{m} & a_{1} [< 0 ) ==> a_{n} és decreishent
a_{n+1} = a_{n}+a_{1} >] a_{n}
a_{n+1} = a_{n}+a_{1} [< a_{n}
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