negació de desigualtat

Sigui A totalment ordenat.

¬( x [< y ) <==> y < x

[<==] absurd

x [< y & ( y [< x & y != x )

[==>]

( x [< y || y [< x ) & ¬( x [< y)

y [< x & ¬( x [< y )

y [< x & ( ¬( x [< y ) || ¬( y [< x ) )

y [< x & y != x

destructor algebràic

d_{x}[x^{(n+1)}] = (-1)·(n+1)·x^{n}

d_{x}[x^{(n+1)}] = (-n)·x^{n}+(-1)·x^{n}

int[x^{n}] d[x] = (-1)·(1/(n+1))·x^{(n+1)}

int[x^{n}] d[x] = ((-n)+(-1))·x^{(-n)+(-1)}

cadenes de funcions - topología algebràica

f(x) = y+x

g(x) = (-y)+x

cadena per composició:

   0 ----> f(0)   ---->...(n)...---->   (fo...(n)...of)(0)

(-0) ----> g(-0) ---->...(n)...----> (go...(n)...og)(-0)

f(x) = yx

g(x) = (1/y)·x

   1 ---->    f(1)   ---->...(n)...---->   (fo...(n)...of)(1)

(1/1) ----> g(1/1) ---->...(n)...----> (go...(n)...og)(1/1)

f(x) = ln(x)

g(x) = e^{x} = exp(x)

1 ---->  f(1)   ---->...(n)...---->   (fo...(n)...of)(exp(...(n)...exp(0)...(n)...))

0 ----> g(0)   ---->...(n)...---->    (go...(n)...og)(ln(...(n)...ln(1)...(n)...))

f_{n}(x) = n^{k}+x

g_{n}(x) = (-1)·n^{k}+x

   0 ---->  f_{1}(0)   ---->...(n)...---->   (f_{n}o...(n)...of_{1})(0)

(-0) ----> g_{1}(-0) ---->...(n)...---->    (g_{n}o...(n)...og_{1})(-0)

f_{n}(x) = n^{k}·x

g_{n}(x) = (1/n^{k})·x

1      ---->  f_{1}(1)   ---->...(n)...---->   (f_{n}o...(n)...of_{1})(1)

(1/1) ----> g_{1}(1/1)   ---->...(n)...---->  (g_{n}o...(n)...og_{1})(1/1)

f(x^{n}) = d_{x}[ x^{n} ]

g(x^{(1/n)}) = d_{x}[ x^{(1/n)} ]

1 ---->  f(1)   ---->...(n)...---->   (fo...(n)...of)(1)

1 ----> g(1)   ---->...(n)...---->    (go...(n)...og)(1)

f(x^{(-n)}) = d_{x}[ x^{(-n)} ]

g(x^{(1/(-n))}) = d_{x}[ x^{(1/(-n))} ]

1 ---->  f(1)   ---->...(n)...---->   (fo...(n)...of)(1)

1 ----> g(1)   ---->...(n)...---->    (go...(n)...og)(1)

lavabo-habitación según l'evangelio borroso stronikián

En mi piso tengo tres habitaciones de cuatro compartimentos de casa.

P(x) = (3/4)

|xxx|-|o|

En mi piso tengo un lavabo de cuatro compartimentos de casa.

¬P(x) = (1/4) 

|ooo|-|x|

cons lasers

volum de un con:

int[ 0--> h ][ 2pi·R·(x/h) ] d[x] = pi·R·h

P·pi·R·h = h_{e}f

P·pi·R·h = (-1)·h_{e}f

destructor algebraic

a+...(n)...+a+a+...(m)...+a+a = (n+m)·a+a

(-a)+...(n)...+(-a)+(-a)+...(m)...+(-a)+(-a) = (-1)·(n+m)·a+(-a)

a+...(n)...+a+a+...(m)...+a = (-1)·(n+m)·a

a+...(n)...+a+a+...(m)...+a = (-n)·a+(-m)·a

(-a)+...(n)...+(-a)+(-a)+...(m)...+(-a) = (n+m)·a

(-a)+...(n)...+(-a)+(-a)+...(m)...+(-a) = na+ma

a·...(n)...·a·a·...(m)...·a·a = a^{(n+m)}·a

(1/a)·...(n)...·(1/a)·(1/a)·...(m)...·(1/a)·(1/a) = a^{(-1)·(n+m)}·(1/a)

a·...(n)...·a·a·...(m)...·a = a^{(-1)·(n+m)}

a·...(n)...·a·a·...(m)...·a = (1/a^{n})·(1/a^{m})

(1/a)·...(n)...·(1/a)·(1/a)·...(m)...·(1/a) = a^{(n+m)}

(1/a)·...(n)...·(1/a)·(1/a)·...(m)...·(1/a) = a^{n}·a^{m}

mis nombres

nombre Judío-cristiano:

Sant Jûan l'stronikián.

nombre islámico:

Jûanathád l'stronikián.

dual de Anathana.