martes, 27 de abril de 2021

operador

A[f(x)] = n·( f(x) )^{m}+m·( f(x) )^{n}

d_{x}[ A[f(x)] ] = mn·A[f(x)]·( d_{x}[f(x)]/f(x) )

d_{x}[ A[x] ] = mn·A[x]·( 1/x )

d_{x}[ A[(1/x)] ] = mn·A[(1/x)]·( ln(x)·x )

d_{x}[ A[e^{x}] ] = mn·A[e^{x}]

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