m_{1}·d_{tt}^{2}[x_{1}] = T+(-k)·x_{1}
m_{2}·d_{tt}^{2}[x_{2}] = F+(-T)
( m_{1}+m_{2} )·d_{tt}^{2}[x] = F+(-k)·x
x(t) = cos( ( k/(m_{1}+m_{2}) )^{(1/2)}·t )+i·sin( ( k/(m_{1}+m_{2}) )^{(1/2)}·t )+( F/k )
T = F+m_{2}·( cos( ( k/(m_{1}+m_{2}) )^{(1/2)}·t )+i·sin( ( k/(m_{1}+m_{2}) )^{(1/2)}·t ) )
No hay comentarios:
Publicar un comentario