viernes, 24 de septiembre de 2021

ecuació de la recta y pla tangent

Ecuació de la recta tangent:

u(x) = d_{x}[f(a)]·(x+(-a))+f(a)

Sigui f(x) = x^{2} ==>

u(x) = 2a·(x+(-a))+a^{2}

Sigui f(x) = x ==>

u(x) = x


Ecuació de pla tangent:

u(x,y) = d_{x}[F(a,b)]·(x+(-a))+d_{y}[F(a,b)]·(y+(-b))+F(a,b)

Sigui F(x,y) = x^{2}+y^{2} ==>

u(x,y) = 2a·(x+(-a))+2b·(y+(-b))+( a^{2}+b^{2} )

Sigui F(x,y) = x+y ==>

u(x,y) = x+y

F(x_{j}) és diferenciable <==> F(x_{j}) té hyper-pla tangent <==> ...

... [ED][ D[F(x_{j})] = < d_{x_{1}}[F_{1}(x_{j})],...,d_{x_{n}}[F_{n}(x_{j})] > ].


F(x_{j}) = ...

... int[ d_{x_{1}}[F_{1}(x_{j})] ] d[x_{1}]+...+int[ d_{x_{n}}[F_{n}(x_{j})] ] d[x_{n}]


f(x) = nx^{n+(-1)}+ny^{n+(-1)}·d_{x}[y]

int[ f(x) ]d[x] = x^{n}+y^{n}

y(x) = ( int[ f(x) ]d[x]+(-1)·x^{n} )^{(1/n)}


f(x) = nx^{n+(-1)}+(1/y)·d_{x}[y]

int[ f(x) ]d[x] = x^{n}+ln(y)

y(x) = e^{( int[ f(x) ]d[x]+(-1)·x^{n} )}


f(x) = nx^{n+(-1)}+e^{y}·d_{x}[y]

int[ f(x) ]d[x] = x^{n}+e^{y}

y(x) = ln( int[ f(x) ]d[x]+(-1)·x^{n} )


ecuacions diferencials:

f(x) = nx^{n+(-1)}+mx^{m+(-1)}·d_{x}[y]

int[ f(x) ]d[x] = x^{n}+( x^{m} [o(x)o] y )

y(x) = ( ( int[ f(x) ]d[x]+(-1)·x^{n} )/o(x)o/x^{m} )


f(x) = y^{n}+d_{x}[y]

y(x) = [[(1/(-n)+1)]]( ( (-1)·((-n)+1) )^{(-n)+1}·x , ( int[ f(x) ]d[x] )^{(-n)+1} )


f(x) = e^{y}+d_{x}[y]

y(x) = ln( [[(-1)]]( x , ( e^{int[ f(x) ]d[x]} )^{(-1)} ) )


f(x) = e^{ny}+d_{x}[y]

y(x) = ln( [[(-1)·(1/n)]]( x , ( e^{int[f(x)]d[x]} )^{(-n)} ) )


d_{x}[ h( [[k]](f(x),g(x)) ) ] = ...

... d_{[[k]](f(x),g(x))}[ h( [[k]](f(x),g(x)) ) ]·k·[[k+(-1)]](f(x),g(x))·d_{x}[f(x)]+...

... d_{x}[ h( ( g(x) )^{k} ) ] )


f(x) = ( ln(y) )^{n}+d_{x}[y]

y(x) = ...

.... e^{ [[e[(-1)]-pow[(1/((-n)+1))]]]( (-1)·((-n)+1)·x , ...

... e[1]-pow[(-1)·(1/((-n)+1))]( ln( int[f(x)][x] ) ) ) }

f(x) = ( ln(1/y) )^{n}+d_{x}[y]

y(x) = ...

... e^{ (-1)·[[e[1]-pow[(1/((-n)+1))]]]( ((-n)+1)·x , ...

... e[(-1)]-pow[(-1)·(1/((-n)+1))]( ln( int[f(x)][x] ) ) ) }


càlcul diferencial 2:

ln-pow[n](x) = x^{n}·ln(x) [o] anti-ln-pow[n](x)

e-pow[n](x) = x^{n}·e^{x} [o] anti-e-pow[n](x)

d_{x}[anti-ln-pow[n](x)] = ( anti-ln-pow[n](x)/(nx+( anti-ln-pow[n](x) )^{n}) )

d_{x}[anti-e-pow[n](x)] = (1/x)·( anti-e-pow[n](x)/(n+( anti-ln-pow[n](x) )) )


d_{x}[y] = ( (x^{n+(-1)}y)/(x^{n}+y^{n}) )

y(x) = anti-ln-pow[n]( x^{n}/n )

d_{x}[y] = ( e^{nx}/(e^{nx}+e^{ny}) )

y = ln(u)

d_{x}[u] = ( (e^{nx}u)/(e^{nx}+u^{n}) )

y(x) = ln( anti-ln-pow[n]( e^{nx}/n ) )


d_{x}[y] = ( my/(n+y) )·(1/x)

y(x) = anti-e-pow[n]( x^{m} )

d_{x}[y] = ( my/(n+y) )

y(x) = anti-e-pow[n]( e^{mx} )


F(x,y) = kx+(n+(-k))·y+h( px+qy+(-m) )

0 = k+hp

0 = (n+(-k))+hq

0 = kx+hpx

0 = (n+(-k))y+hqy

0 = kx+(n+(-k))y+hm

h = (-1)·(n/m)

x = 1

y = 1

F(x,y) = kx+(n+(-k))·y+h( px+qy+(-m) )

F(1,1) = n

G(x,y) = kx+(n+(-k))·y+h( px+qy )

G(1,1) = 0


F(x,y) = x^{k}+y^{n+(-k)}+h( px+qy+(-m) )

0 = kx^{k+(-1)}+hp

0 = (n+(-k))·y^{n+(-k)+(-1)}+hq

0 = kx^{k+(-1)}+(n+(-k))y^{n+(-k)+(-1)}+hm

h = (-1)·( (k^{k}+(n+(-k))^{n+(-k)})/m )

x = k

y = (n+(-k))

F(x,y) = x^{k}+y^{n+(-k)}+h( px+qy+(-m) )

F(k,n+(-k)) = k^{k}+(n+(-k))^{n+(-k)}

G(x,y) = x^{k}+y^{n+(-k)}+h( px+qy )

G(k,n+(-k)) = 0


F(x,y) = ke^{x}+(n+(-k))e^{y}+h( px+qy+(-m) )

0 = ke^{x}+hp

0 = (n+(-k))e^{y}+hq

0 = ke^{x}+(n+(-k))e^{y}+hm

h = (-1)·(n/m)

x = 0

y = 0

F(x,y) = ke^{x}+(n+(-k))e^{y}+h( px+qy+(-m) )

F(0,0) = n

G(x,y) = ke^{x}+(n+(-k))e^{y}+h( px+qy )

G(0,0) = 0



F(x,y) = e^{kx}+e^{(2+(-k))y}+h( px+qy+(-m) )

0 = ke^{kx}+hp

0 = (2+(-k))e^{(2+(-k))y}+hq

0 = ke^{kx}+(2+(-k))e^{(2+(-k))y}+hm

h = (-1)·(2/m)

x = 0

y = 0

F(x,y) = e^{kx}+e^{(2+(-k))y}+h( px+qy+(-m) )

F(0,0) = 2

G(x,y) = e^{kx}+e^{(2+(-k))y}+h( px+qy )

G(0,0) = 0

jueves, 23 de septiembre de 2021

kung-fu y caminar sin saber a donde vatchnar

dos amantis

|x|-|ooxx|

tres tiburón

|x|-|ooox|


dos hormiga

|o|-|oxxx|

tres águila

|o|-|ooxx|


Dual Luminoso:

Es irreversible la muerte,

no destruyéndote andando.

Quizás Dios te puede poner los símbolos de destrucción

pero no te destruirás,

porque no puedes andar.

Si no te destruyes andando,

no te haces nuevo,

y no puedes tener nueva energía.

Es reversible la muerte,

destruyéndote andando.

Dios te puede poner los símbolos de destrucción

y entonces también te destruirás,

porque puedes andar.

Si te destruyes andando,

te haces nuevo,

y puedes tener nueva energía.

Dual Tenebroso:

Es irreversible-irreversible-reversible la muerte,

no destruyéndote-destruyéndote-construyéndote andando.

Quizás Dios te puede poner los símbolos de destrucción

pero no te destruirás-destruirás-construirás,

porque no puedes andar.

max{0,min{1,(1/3)}} = (1/3)

Si no te destruyes-destruyes-construyes andando,

no te haces nuevo-nuevo-viejo,

y no puedes tener nueva-nueva-vieja energía.

Es reversible-reversible-irreversible la muerte,

destruyéndote-destruyéndote-construyéndote andando.

Dios te puede poner los símbolos de destrucción

y entonces también te destruirás-destruirás-construirás,

porque puedes andar.

min{1,max{0,(2/3)}} = (2/3)

Si te destruyes-destruyes-construyes andando,

te haces nuevo-nuevo-viejo,

y puedes tener nueva-nueva-vieja energía.


Dual Luminoso:

El que camina sin saber a donde vatchnar con lo pie derecho,

se destruye.

El que camina sin saber a donde vatchnar con lo pie izquierdo,

se construye.

Dual Tenebroso:

El que camina sin saber a donde vatchnar con lo pie derecho-derecho-izquierdo,

se destruye-destruye-construye.

El que camina sin saber a donde vatchnar con lo pie izquierdo-izquierdo-derecho,

se construye-construye-destruye.


Dual Luminoso:

Si llueve entonces se moja porque no lleva paraguas.

Llueve y no se moja aunque quizás no lleva paraguas.

Dual Tenebroso:

Si llueve entonces se moja-moja-seca porque no lleva paraguas.

min{max{max{0,(2/3)},0},1} = (2/3)

Llueve y no se moja-moja-seca aunque quizás no lleva paraguas.

max{min{min{1,(1/3)},1},0} = (1/3)

martes, 21 de septiembre de 2021

analisis matemàtic: continuitat

Continuitat:

[As][ s > 0 ==> [Ed][ d > 0 & ( Si |x+(-a)| < d ==> |f(x)+(-1)·f(a)| < s ) ] ]

[As][ s > 0 ==> [Ed][ d > 0 & ( Si |h| < d ==> |f(a+h)+(-1)·f(a)| < s ) ] ]

[As][ s > 0 ==> [Ed][ d > 0 & ( Si |(-h)| < d ==> |f(a+(-h))+(-1)·f(a)| < s ) ] ]


lim[a-->h][ | ln(1+(h/a)) | ] = ln(2) >] s

ln(x) no és contínua a x = 0

lim[a-->h][ | (-h)/((a+h)·a) | ] = (1/2)·oo >] s

(1/x) no és contínua a x = 0

lim[a-->h][ | 0^{2}/((a+h)·a) | ] = (1/2) >] s 

(x/x) no és contínua a x = 0


lim[a-->h][ | 0^{2}/((a+h+(-a))·(a+(-a)) | ] = 1 >] s 

( (x+(-a))/(x+(-a)) ) no és contínua a x = a

lim[a-->h][ | 0^{2}/(((-a)+h+a)·((-a)+a)) | ] = 1 >] s 

( (x+a)/(x+a) ) no és contínua a x = (-a)


Si f(x) es contínua ==> ( f(x) )^{n} és contínua.

lim[h-->0][ | ( f(x)+h )^{n}+(-1)·( f(x) )^{n} | ] = 0 < s

 

Sigui: [Ax][ 0 [< ( f(x) )^{n} [< |x| ] ==>

f(0) = 0

0 [< f(1) [< 1

Teorema destructor:

Si f(x) [< x ==> |f(x)+(-x)+h| < |x+(-x)+h|

Si f(x) >] x ==> |f(x)+(-x)+h| < |x+(-x)+h|

Teorema destructor:

Sigui s > 0 ==>

Es defineish: 0 < d [< s ==>

Si |x+(-1)| [< d ==>

|f(1+h)+(-1)·f(1)| [< | |1+h|^{(1/n)}+(-1)·f(1) | = ...

... |(1+h)^{(1/n)}+(-1)·f(1)| [< ...

... |(1+h)+(-1)·f(1)| = |f(1)+(-1)·(1+h)| < |1+(-1)+(-h)| = |(-h)| = |x+(-1)| [< d [< s

f(x) no és contínua en x = 1

0 [< f(-1) [< 1

Teorema destructor:

Si f(x) [< x ==> |f(x)+(-x)+h| < |x+(-x)+h|

Si f(x) >] x ==> |f(x)+(-x)+h| < |x+(-x)+h|

Teorema destructor:

Sigui s > 0 ==>

Es defineish: 0 < d [< s ==>

Si |x+1| [< d ==>

|f( (-1)+(-h) )+(-1)·f(-1)| [< | |(-1)+(-h)|^{(1/n)}+(-1)·f(-1) | = ...

... |(1+h)^{(1/n)}+(-1)·f(-1)| [< ...

... |(1+h)+(-1)·f(-1)| = |f(-1)+(-1)·(1+h)| < |1+(-1)+(-h)| = |(-h)| = |x+1| [< d [< s

f(x) no és contínua en x = (-1)


Si f(x) es contínua ==> |f(x)| és contínua.

Si f(x) >] 0 ==> lim[h-->0][ | |f(x)+h|+(-1)·|f(x)| | ] = 0 < s

Si f(x) [< 0 ==> lim[h-->0][ | |f(x)+(-h)|+(-1)·|f(x)| | ] = 0 < s


Sigui: [Ax][ 0 [< |f(x)| [< |x| ] ==>

f(0) = 0

0 [< |f(1)| [< 1

Teorema destructor:

Si f(x) [< x ==> |f(x)+(-x)+h| < |x+(-x)+h|

Si f(x) >] x ==> |f(x)+(-x)+h| < |x+(-x)+h|

Teorema destructor:

Sigui s > 0 ==>

Es defineish: 0 < d [< s ==>

Si |x+(-1)| [< d ==>

| |f(1+h)|+(-1)·|f(1)| | [< | |1+h|+(-1)·|f(1)| | = ...

... | |f(1)|+(-1)·|1+h| | < | 1+(-1)·|1+h| | = |(-h)| = |x+(-1)| [< d [< s

f(x) no és contínua en x = 1

0 [< |f(-1)| [< 1

Teorema destructor:

Si f(x) [< x ==> |f(x)+(-x)+h| < |x+(-x)+h|

Si f(x) >] x ==> |f(x)+(-x)+h| < |x+(-x)+h|

Teorema destructor:

Sigui s > 0 ==>

Es defineish: 0 < d [< s ==>

Si |x+1| [< d ==>

| |f((-1)+(-h))|+(-1)·|f(-1)| | [< | |(-1)+(-h)|+(-1)·|f(-1)| | = ...

... | |f(-1)|+(-1)·|(-1)+(-h)| | < | 1+(-1)·|(-1)+(-h)| | = |(-h)| = |x+1| [< d [< s

f(x) no és contínua en x = (-1)


[Ax][ 0 [< ( f(x) )^{n} [< |x| ]

f(x) = ( |x|^{2}/(|x+1|·|x+(-1)|) )^{(1/n)}

[Ax][ 0 [< |f(x)| [< |x| ]

f(x) = ( x^{2}/( (x+1)·(x+(-1)) ) )

|x^{2}| = |x·x| = |x|·|x| = |x|^{2}

topología

E_{k} = { x€[0,oo]_{K} : x < a_{1}+...(k)...+a_{k} }

F_{k} = { x€[0,oo]_{K} : a_{1}+...(k)...+a_{k} [< x }

Si x < S_{m} [< a_{1}+...(k)...+a_{k} [< S_{n} ==>

E_{n} = E_{m}[ || ]...(k)...[ || ]E_{n}

E_{m} = E_{m}[ & ]...(k)...[ & ]E_{n}

E_{m} [<< ...(k)... [<< E_{n}

Si S_{m} [< a_{1}+...(k)...+a_{k} [< S_{n} [< x ==>

F_{m} = F_{n}[ || ]...(k)...[ || ]F_{m}

F_{n} = F_{n}[ & ]...(k)...[ & ]F_{m}

F_{n} [<< ...(k)... [<< F_{m}


G_{k} = { x€[0,oo]_{K} : x [< a_{1}+...(k)...+a_{k} }

H_{k} = { x€[0,oo]_{K} : a_{1}+...(k)...+a_{k} < x }

Si x [< S_{m} [< a_{1}+...(k)...+a_{k} [< S_{n} ==>

G_{n} = G_{m}[ || ]...(k)...[ || ]G_{n}

G_{m} = G_{m}[ & ]...(k)...[ & ]G_{n}

G_{m} [<< ...(k)... [<< G_{n}

Si S_{m} [< a_{1}+...(k)...+a_{k} [< S_{n} < x ==>

H_{m} = H_{n}[ || ]...(k)...[ || ]H_{m}

H_{n} = H_{n}[ & ]...(k)...[ & ]H_{m}

H_{n} [<< ...(k)... [<< H_{m}


Homotopía:

[Es][ f(1,0) = g(1,0)+s ] & [Es][ f(0,1) = g(0,1)+s ]

reflexiva

s = f(1,0)+(-1)·g(1,0) & s = f(0,1)+(-1)·g(0,1)

simétrica:

Es defineish: t = (-s)

transitiva:

Es defineish: t = s_{1}+s_{2}


f: { x }x{ y } ---> { x^{2}+y^{2} } & ...

... < x,y > ---> f(x,y) = x^{2}+y^{2}

f(0,1) = 1

f(1,0) = 1

f: { x^{2} }x{ y^{2} } ---> { x^{2}+y^{2} } & ...

... < x,y > ---> f(x,y) = x+y

f(0,1) = 1

f(1,0) = 1

f: { xy }x{ yx } ---> { x^{2}+y^{2} } & ...

... < x,y > ---> f(x,y) = (1/y)^{2}·x^{2}+(1/x)^{2}·y^{2}

f(0,1) = oo^{2}

f(1,0) = oo^{2}

f: { x+y }x{ y+x } ---> { x^{2}+y^{2} } & ...

... < x,y > ---> f(x,y) = (x+(-y))^{2}+(y+(-x))^{2}

f(0,1) = 2

f(1,0) = 2

f: { x^{2}+y }x{ y^{2}+x } ---> { x^{2}+y^{2} } & ...

... < x,y > ---> f(x,y) = (x+(-y))+(y+(-x))

f(0,1) = 0

f(1,0) = 0


f: { g(x) }x{ g(y) } ---> { x^{2}+y^{2} } & ...

... < x,y > ---> f(x,y) = ( g^{o(-1)}(x) )^{2}+( g^{o(-1)}(y) )^{2}

f(0,1) = ( g^{o(-1)}(1) )^{2}+( g^{o(-1)}(0) )^{2}

f(1,0) = ( g^{o(-1)}(0) )^{2}+( g^{o(-1)}(1) )^{2}

f: { g(x)+y }x{ g(y)+x } ---> { x^{2}+y^{2} } & ...

... < x,y > ---> f(x,y) = ( g^{o(-1)}(x+(-y)) )^{2}+( g^{o(-1)}(y+(-x)) )^{2}

f(0,1) = ( g^{o(-1)}(-1) )^{2}+( g^{o(-1)}(1) )^{2}

f(1,0) = ( g^{o(-1)}(1) )^{2}+( g^{o(-1)}(-1) )^{2}

lunes, 20 de septiembre de 2021

stowed-kah y stehed-kah

present-toh:

I smehnish-koh

I stare-koh smehning-kah

I havere-koh smehned-kah

imperfect-toh:

I stave-koh smehning-kah

I havíe-koh smehned-kah

Anterior-toh

vare-koh smehnish-koh

vare-koh stader-koh smehning-kah

vare-koh havader-koh smehned-kah

subjuntive-toh:

I stuviese-koh smehning-kah

I huviese-koh smehned-kah


plat-matchéh.

plate-matchéh.


I gowish-koh ur-rapidi-kowish-kah to my haws-matchéh.

I gowish-koh ur-lenti-kowish-kah to my haws-matchéh.


I gehish-koh ur-rapidi-kehish-kah to my haws-matchéh.

I gehish-koh ur-lenti-kehish-kah to my haws-matchéh.


my tranke-matchéh stare-koh ur-duri-kowish-kah,

becose I stare-koh anai-ed-bero-kowish-kah.

my tranke-matchéh stare-koh ur-blandi-kowish-kah,

becose I stare-koh anai-ed-otza-kowish-kah.


my tranke-matchéh stare-koh ur-duri-kehish-kah,

becose I stare-koh anai-ed-bero-kehish-kah.

my tranke-matchéh stare-koh ur-blandi-kehish-kah,

becose I stare-koh anai-ed-otza-kehish-kah.


I havere-koh smoked-kah a biturbi-kowish-kah.

I havere-koh smoked-kah a ele-kowish-kah.


I havere-koh smehned-kah a biturbi-kehish-kah.

I havere-koh smehned-kah a ele-kehish-kah.


I stare-koh drinking-kah a fante-matchéh of lemon-koh.

I stare-koh drinking-kah a fante-matchéh of oransh-koh.


I stare-koh trinking-kah a fante-matchéh of lemon-koh.

I stare-koh trinking-kah a fante-matchéh of oransh-koh.

derivades

d_{x}[a^{x}] = e^{x}·ln(a)

d_{log_{a}(x)}[a^{log_{a}(x)}]·d_{x}[log_{a}(x)] = 1

e^{log_{a}(x)}·ln(a)·d_{x}[log_{a}(x)] = 1

e^{log_{a}(e^{ln(x)})}·ln(a)·d_{x}[log_{a}(x)] = 1

d_{x}[log_{a}(x)] = (1/x)^{log_{a}(e)}·(1/ln(a))


log_{a}(x) = ( 1/(ln(a)+(-1)) )·x^{(1+(-1)·log_{a}(e))}


a^{x} = e^{ln(a)·x}

1 = log_{a}(e)·ln(a)

sábado, 18 de septiembre de 2021

stowed & stehed

beber:

drink <==> trink

drinkems <==> trinkems

drinkez <==> trinkez

drinken <==> trinken

drogar:

druck <==> truck

druckems <==> truckems

druckez <==> truckez

drucken <==> trucken


drash <==> trash

drashems <==> trashems

drashez <==> trashez

drashen <==> trashen


sdratch <==> stratch

sdratchems <==> stratchems

sdratchez <==> stratchez

sdratchen <==> stratchen


morir:

mordrate <==> mortrate

mordrems <==> mortrems

mordrez <==> mortrez

mordren <==> mortren

moler:

moldrate <==> moltrate

moldrems <==> moltrems

moldrez <==> moltrez

moldren <==> moltren


sdirt <==> stirt

sdirtems <==> stirtems

sdirtez <==> stirtez

sdirten <==> stirten


sdilt <==> stilt

sdiltems <==> stiltems

sdiltez <==> stiltez

sdilten <==> stilten


If I huviese-kate mordrated,

I not estaríe-kate speaking here.

If I huviese-kate mortrated,

I not estaríe-kate spehning here.


When snowest,

I not gowest to the discotek.

When snehest,

I not gehest to the tiscotek.


If wies huviese-kems drinked,

wies starie-kems drucked.

If wies huviese-kems trinked,

wies starie-kems trucked.


I srakest the window,

and I close de dor.

I srehnest the window,

and I close de tor.


I pustate the paper on the dish.

I pusgate the paper on the tish.


I stare-kate foted,

speaking stowed.

I stare-kate fot-hed,

spehning stehed.


wies vare-kems stader making a coteds yesterday in a bar.

wies vare-kems stader mehming a cot-heds yesterday in a bar.


Times of the verbs:

present:

drink

stare-kate drinking

havere-kate drinked.

stare-kate caning drink

havere-kate caned drink

imperfect:

stave-kate drinking

havíe-kate drinked.

stave-kate caning drink

havíe-kate caned drink.

anterior:

vare-kate drink

vare-kate stader drinking

vare-kate havader drinked.

vare-kate stader caning drink

vare-kate havader caned drink

subjuntive:

stuviese-kate drinking

huviese-kate drinked.

stuviese-kate caning drink

huviese-kate caned drink

condicional:

staríe-kate drinking

hauríe-kate drinked.

staríe-kate caning drink

hauríe-kate caned drink

futur:

starete-kate drinking

haurete-kate drinked.

starete-kate caning drink

haurete-kate caned drink


If I huviese-kate comprated,

I staríe-kate caning drink.

If I huviese-kate comprated,

I staríe-kate caning trink.


I not stare-kate caning drink,

I not have sugar-drinks.

I not stare-kate caning trink,

I not have sugar-trinks.