evangelio stronikián y física

Tenemos 3 panes y 2 peces,

que no son pares pan-pez,

y vamos a tener más de 3 pares pan-pez.

No tenemos 3 panes o 2 peces,

que son pares pan-pez,

y no vamos a tener más de 3 pares pan-pez.

tenemos 3 panes y 3 peces.

tenemos 2 panes y 2 peces.

tenemos 1 pan y 1 pez.

Lley:

Sea A(x,y) un hombre que está de pié y está inclinado,

y sea F la fuerza de resistencia del suelo del pié al centro de masas:

m·d_{tt}^{2}[y] = (-1)·qg+F·cos(s)

m·d_{tt}^{2}[x] = F·sin(s)+(-1)·k·F·cos(s)

A(x,y) está en equilibri <==> ( tan(s) [< k & F = ( (qg)/cos(s) ) )

Deducció:

Sea cos(s) > 0

F·cos(s) = qg

F = ( (qg)/cos(s) )

F·sin(s) [< k·F·cos(s)

sin(s) [< k·cos(s)

tan(s) [< k

Lley:

Sea A(x,y) una caja en un plano inclinado,

y sea F la fuerza de resistencia del suelo:

m·d_{tt}^{2}[y] = (-1)·qg·cos(s)+F

m·d_{tt}^{2}[x] = qg·sin(s)+(-1)·k·F

A(x,y) está en equilibri <==> ( tan(s) [< k & F = qg·cos(s) )

Deducció:

Sea cos(s) > 0

F = qg·cos(s)

qg·sin(s) [< k·F

qg·sin(s) [< k·qg·cos(s)

sin(s) [< k·cos(s)

tan(s) [< k

Lley:

Sea A(x,y) una caja en lo plano y una caja colgada de una polea,

y sea F la fuerza de resistencia del suelo con la caja del plano:

m_{1}·d_{tt}^{2}[y] = (-1)·qg+F

(m_{1}+m_{2})·d_{tt}^{2}[x] = pg+(-1)·k·F

A(x,y) está en equilibri <==> ( (p/q) [< k & F = qg )

T = ( (p·m_{1}+kq·m_{2})/(m_{1}+m_{2}) )·g

protón:

m = (0.9)·uma

neutrón:

m = (0.9)·uma

electrón:

m = (0.2)·uma

Átomo de hidrógeno:

m = 2 uma

1 mol de hidrógeno tiene masa 2 Kg.

1 Kg = 10^{23} uma

1 g = 10^{20} uma

quark:

m = (0,3) uma

Potencial de fusión nuclear:

E(t)·e^{(-1)}+E(t)·e^{(-1)} = 2·E(t)·e^{(-1)} = 2·E(t)·e^{(-2)}+G_{2}(t)

2·E(t)·e^{(-2)}+2·E(t)·e^{(-2)} = 4·E(t)·e^{(-2)} = 4·E(t)·e^{(-4)}+G_{4}(t)

G_{2}(t) = 2·E(t)·e^{(-2)}( e+(-1) )

G_{4}(t) = 4·E(t)·e^{(-4)}( e^{2}+(-1) )

Ecuacions de Maxwell electro-magnétiques en un cub:

Principi:

E_{e}(x,y,z) = qk_{e}·(1/r^{2})·(< x,y,z >/r)

B_{e}(x,y,z) = (-1)·qk_{e}·(1/r^{2})·(< d_{t}[x],d_{t}[y],d_{t}[z] >/r)

Lley:

anti-potencial[ E_{e}(r,r,r) ] = 3qk_{e}

anti-potencial[ B_{e}(r,r,r) ] = (-0)

Lley:

anti-potencial[ rot[ E_{e}(x,y,z) ] ] = ...

... qk_{e}+int[ anti-potencial[ B_{e}(r,r,r) ] ]d[t]

anti-potencial[ rot[ B_{e}(x,y,z) ] ] = ...

... d_{t}[q(t)]·k_{e}+(-1)·(1/3)·d_{t}[ anti-potencial[ E_{e}(r,r,r,q(t)) ] ]

Lley:

rot[ E_{e}(x,y,z) ] = H_{e}(x,y,z)+int[ B_{e}(r,r,r) ]d[t]

rot[ B_{e}(x,y,z) ] = J_{e}(x,y,z,q(t))+(-1)·(1/3)·d_{t}[ E_{e}(r,r,r,q(t)) ]

Lley:

H_{e}(x,y,z) = rot[ E_{e}(x,y,z) ]+qk_{e}·(1/r^{2})·< 1,1,1 >

J_{e}(x,y,z,q(t)) = rot[ B_{e}(x,y,z) ]+(1/3)·d_{t}[q(t)]·k_{e}·(1/r^{2})·< 1,1,1 >

Lley:

Si ( E_{e}(x,y,z) = 0 & hi ha inducció magnética ) ==> ...

... hi ha cárrega. [ T = R·q ]

Si ( B_{e}(x,y,z) = 0 & hi ha corrent de desplaçament de diferencia de cárrega ) ==> ...

... hi ha intensitat del corrent. [ A = R·d_{t}[q(t)] ]

Lley:

m·d_{tt}^{2}[x] = p·( E_{e}(x)+int[ B_{e}(x) ]d[t] )

x(t) = vt

Ecuacions de Maxwell gravito-magnétiques en un cub:

Principi:

E_{g}(x,y,z) = (-1)·qk_{g}·(1/r^{2})·(< x,y,z >/r)

B_{g}(x,y,z) = qk_{g}·(1/r^{2})·(< d_{t}[x],d_{t}[y],d_{t}[z] >/r)

Lley:

anti-potencial[ E_{g}(r,r,r) ] = (-3)·qk_{g}

anti-potencial[ B_{g}(r,r,r) ] = 0

Lley:

anti-potencial[ rot[ E_{g}(x,y,z) ] ] = ...

... qk_{g}+(-1)·int[ anti-potencial[ B_{g}(r,r,r) ] ]d[t]

anti-potencial[ rot[ B_{g}(x,y,z) ] ] = ...

.. d_{t}[q(t)]·k_{g}+(1/3)·d_{t}[ anti-potencial[ E_{g}(r,r,r,q(t)) ] ]

Lley:

rot[ E_{g}(x,y,z) ] = H_{g}(x,y,z)+(-1)·int[ B_{g}(r,r,r) ]d[t]

rot[ B_{g}(x,y,z) ] = J_{g}(x,y,z,q(t))+(1/3)·d_{t}[ E_{g}(r,r,r,q(t)) ]

Lley:

H_{g}(x,y,z) = rot[ E_{g}(x,y,z) ]+qk_{g}·(1/r^{2})·< 1,1,1 >

J_{g}(x,y,z,q(t)) = rot[ B_{g}(x,y,z) ]+(1/3)·d_{t}[q(t)]·k_{g}·(1/r^{2})·< 1,1,1 >

Lley:

m·d_{tt}^{2}[x] = p·( E_{g}(x)+int[ B_{g}(x) ]d[t] )

x(t) = vt

mecánica clásica

l = longitud del hombre de pié.

somier:

m·d_{tt}^{2}[z(t)] = P·l·( x+y )

z(t) = A·e^{2^{(1/2)}·( (P·l)/m )^{(1/2)}·t}

colchón:

m·d_{tt}^{2}[z(t)] = (-1)·P·l·( x+y )

z(t) = A·e^{2^{(1/2)}·( (P·l)/m )^{(1/2)}·it}

váter:

m·d_{tt}^{2}[z(t)] = P·( x^{2}+y^{2} )

z(t) = ( (1/3)^{(1/2)}·(P/m)^{(1/2)}·t )^{(-2)}

ducha:

m·d_{tt}^{2}[z(t)] = (-P)·( x^{2}+y^{2} )

z(t) = ( (1/3)^{(1/2)}·(P/m)^{(1/2)}·it )^{(-2)}

sofá-derecho

m·d_{tt}^{2}[z(t)] = (P/l)·( x^{3}+y^{3} )

z(t) = ( ( P/(m·l) )^{(1/2)}·t )^{(-1)}

sofá-izquierdo

m·d_{tt}^{2}[z(t)] = (-1)·(P/l)·( x^{3}+y^{3} )

z(t) = ( ( P/(m·l) )^{(1/2)}·it )^{(-1)}

No desearás nada que le pertenezca al prójimo:

Si no sois del Gestalt,

no hagáis modus ponens de este blog,

que se convierte en destrocter ponens contra vosotros.

Desearás algo que le pertenezca al próximo:

Si sois del Gestalt,

haced modus ponens de este blog,

que no se convierte en destrocter ponens contra vosotros.

d_{x}[u(x,y)]+d_{y}[u(x,y)] = f(x)+g(y)

u(x,y) = int[ f(x) ]d[x]+int[ g(y) ]d[y]

d_{x}[u(x,y)]+d_{y}[u(x,y)] = x+y

u(x,y) = ( (1/2)·x^{2}+(1/2)·y^{2} )

d_{x}[u(x,y)] = x

d_{y}[u(x,y)] = y

d_{x}[u(x,y)]+d_{y}[u(x,y)] = x·y

u(x,y) = (1/4)·( yx^{2}+(-1)·(1/3)·x^{3}+xy^{2}+(-1)·(1/3)·y^{3} )

d_{x}[u(x,y)] = 2yx+(-1)·x^{2}+y^{2}

d_{y}[u(x,y)] = 2xy+(-1)·y^{2}+x^{2}

curvas elípticas:

elipses de coordenada: < cos[n](t),sin[n](t) >

cos[n](0) = n

sin[n](0) = 0

cos[n](pi/2) = ( n^{n+1}+(-1) )^{(1/(n+1))}

sin[n](pi/2) = 1

cos[n](pi) = (-n)

sin[n](pi) = 0

cos[n]( (-1)·(pi/2) ) = ( (-1)·(-n)^{n+1}+1 )^{(1/(n+1))}

sin[n]( (-1)·(pi/2) ) = (-1)

sin[n](x) = sum[ (-1)^{k_{1}...k_{n}}·( 1/(2·(k_{1}...k_{n})+1)! )·...

... (x/n)^{2·(k_{1}...k_{n})+1} ]

cos[n](x) = sum[ (-1)^{k_{1}...k_{n}}·( 1/(2·(k_{1}...k_{n}))! )·...

... (x/n)^{2·(k_{1}...k_{n})} ]

lim[ x --> 0 ][ ( sin[n](x)/x ) ] = 1

física de infieles y condenación

Juego amar ganando lo máximo.

porque es positivo lo juego 2n.

amar a un fiel:

< n,n >

F(n) = n^{2}+2n

amar a un infiel:

< (-n),n >

F(n) = (-1)·n^{2}

Juego odiar ganando lo mínimo,

porque es negativo lo juego (-2)·n.

odiar a un fiel:

< (-n),(-n) >

F(n) = n^{2}+(-2)·n

odiar a un infiel:

< n,(-n) >

F(n) = (-1)·n^{2}

Condenación de Vox:

Juego de las autonomías ganando lo máximo,

porque es positivo lo juego (n+2):

n autonomías

n países soberanos

< n,n >

F(n) = n^{2}+2n

1 autonomía

(-n)+1 países no soberanos

< 1,(-n)+1 >

F(n) = (-2)·n+3

Fuerza membrana-eléctrica:

H_{h,e}(x,y,z) = qk_{h,e}·( 1/r^{4} )·( < x,y,z >/r )

Fuerza membrana-gravitatoria:

H_{h,g}(x,y,z) = (-1)·qk_{h,g}·( 1/r^{4} )·( < x,y,z >/r )

Anti-gravedad real.

Anti-gravedad imaginaria.

Fuerza eléctrica:

E_{e}(x,y,z) = qk_{e}·( 1/r^{2} )·( < x,y,z >/r )

Fuerza gravitatoria:

E_{g}(x,y,z) = (-1)·qk_{g}·( 1/r^{2} )·( < x,y,z >/r )

Anti-gravedad real.

Anti-gravedad imaginaria de Otelo. [ espejo de interrogatorio ]

budismo stronikiano

Caminad con la luz,

mientras tengáis luz,

para que no vos sorprendan las tinieblas,

y lleguéis a la iluminación.

Hasta que l'hombre fiel sienta que no es,

y haga imposible lo sufrimiento de un hombre esclavo infiel,

y de todo lo masculino que no es.

Caminad con lo sonido,

mientras tengáis sonido,

para que no vos sorprenda lo silencio,

y lleguéis a la sonorización.

Hasta que la mujer fiel sienta que no es,

y haga imposible lo sufrimiento de una mujer esclava infiel,

y de todo lo femenino que no es.

Mis amigos:

Áragorn de corona de Aragón:

Països Catalans.

Italia.

Grecia.

Rohan-Occitania.

Bilbao-Bolsón-de-Euskal-Herria.

Mis enemigos:

Mordor-Fachas-Españoles.

Isengard-Fachas-Franceses.

Si ye vule ye-de-muá surtire-dom,

elet-pú a-vot-má,

avec ye-de-muá,

que suy-pas tun mesier.

Si tú vule tú-de-tuá surtire-dom,

elet-pé a-vot-má,

avec tú-de-tuá,

que nets-pas mun madam.

Lley:

Sigui A(x) una escala de longitud = d , recolzada en una pared,

amb fregament P amb el terra y amb fregament Q amb la pared.

Si m·d_{tt}^{2}[x] = (-1)·qg+P+Q ==> ...

... ( A(x) está en equilibri <==> P+Q = qg )

Deducció:

d·P = paralel a (-1)·qg.

(d/2)·( (-1)·qg )+d·P+( (-1)·(d/2) )·qg+( (-1)·d )·( (-1)·Q ) = 0

Lley:

A una taula A(y) de longitud = d , se li apliquen dues forces en els extrems.

Si m·d_{tt}^{2}[y] = 2F+(-T) ==> ...

... ( A(y) está en equilibri <==> T = 2F )

Deducció:

d·( (-1)·F )+( (-1)·d )·F+(d/2)·( (-1)·T )+( (-1)·(d/2) )·T = 0

Sigensmés hi ha seleccions autonómiques

pero sin-embarg no hi ha selecció nacional,

en el model confederal.

( P(x),, & ¬Q(y) )

P(x),, <==> ¬¬( ¬¬P(x) )

Nogensmenys hi ha seleccions autonómiques

y aleshores áduc hi ha selecció nacional,

en el model federal.

( P(x);; ==> Q(y) )

P(x);; <==> ¬¬¬( ¬¬¬P(x) )

ye tingue ye-de-muá que treballare-dom,

y elet-pú tambén.

tú tingue tú-de-tuá que treballare-dom,

y elet-pé tambén.

condicionel:

ye treballe ye-de-muá,

y elet-pú a-vot-má de-le-tóm tambén. [ tindríes que treballar també ]

tú treballe tú-de-tuá,

y elet-pé a-vot-má de-le-tóm tambén. [ tindría que treballar també ]

ye parle ye-de-muá le Françé de le Patuá,

y elet-pú a-vot-má,

que ets-de-puá de Le Franç.

tú parle tú-de-tuá le Françé de le Patuá,

y elet-pé a-vot-má,

que suí-de-puá de Le Franç.

ye sé-pont de-le-com és-de-puá la verité.

ye ne sé-pont de-le-com és-de-puá la verité.

nus soms-de-puá les-des campiuns.

vus soz-de-puá les-des campiuns.

sere-dom [o] estare-dom:

suí-de-puá [o] estuí-de-puá

ets-de-puá [o] estás-de-puá

és-de-puá [o] está-de-puá

soms-de-puá [o] estoms-de-puá

soz-de-puá [o] estoz-de-puá

son-de-puá [o] están-de-puá

contacto conmigo y ventas de video-juegos

Datos para contactar:

Jûan Garriga Peralta-Peraltotzak

Correo electrónico:

drgarriga303@gmail.com

Teléfono:

625 19 87 72

Solo respondo a mensajes.

Vendo:

Zelda de Súper-Nintendo,

caja, juego, instrucciones y mapa,

más 140 años de espíritu santo de videojuego por:

Precio = 1,024,000€ + (-1)·102,400€ = ...

... 200·(llama-violeta)·256·(byte/llama-violeta)·1·(día/byte)·20·(€/día)

Vendo:

Zelda de Nintendo-64,

caja, juego y instrucciones,

más 140 años de espíritu santo de videojuego por:

Precio = 1,024,000€ + (-1)·102,400€ = ...

... 200·(llama-violeta)·256·(byte/llama-violeta)·1·(día/byte)·20·(€/día)

Mentiras que te hacen malo:

se tiene poder ilimitado.

no hay condenación.

no hay esclavos infieles que no son.

se puede conquistar un planeta extraterrestre.

se puede proyectar la mente en un extraterrestre.

[ cuerpo de hombre || de mujer & alma extraterrestre <==> ...

... los infieles hombre || mujer le sacan la luz al extraterrestre ]

se puede recordar las palabras y las experiencias de un fiel que es.

se puede saltar-se algún mandamiento con un fiel que es.

No puede haber ningún fiel en un planeta extraterrestre que no sea un dios,

porque los infieles le sacan toda la luz y muere.

Tetris-Colums-Kúkons:

[x] = 0

[y] = 1

[status] = 1

[m] = 2·[L]+1;

for( [j] = not(1) ; [j] >] not([n]) ; [j]-- )

{

put-grafic( grafic[i][j] , ( centre-x+[i]+2·[x] )·[m] , ( [j]+2·[y] )·[m] );

put-grafic( grafic[i][j] , ( centre-x+[i]+[x] )·[m] , ( [j]+[y] )·[m] );

put-grafic( grafic[i][j] , ( centre-x+[i] )·[m] , [j]·[m] );

put-grafic( grafic[i][j] , ( centre-x+[i]+not([x]) )·[m] , ( [j]+not([y]) )·[m] );

put-grafic( grafic[i][j] , ( centre-x+[i]+2·not([x]) )·[m] , ( [j]+2·not([y]) )·[m] );

if( kbhit-positiu() == 1 & [status] == 1 & ...

... ( [i]+3 [< [p] || [i]+not(3) >] [q] ) )

{

put-grafic( not-grafic[i][j] , ( centre-x+[i]+2·[x] )·[m] , ( [j]+2·[y] )·[m] );

put-grafic( not-tgrafic[i][j] , ( centre-x+[i]+[x] )·[m] , ( [j]+[y] )·[m] );

put-grafic( not-grafic[i][j] , ( centre-x+[i] )·[m] , [j]·[m] );

put-grafic( not-grafic[i][j] , ( centre-x+[i]+not([x]) )·[m] , ( [j]+not([y]) )·[m] );

put-grafic( not-grafic[i][j] , ( centre-x+[i]+2·not([x]) )·[m] , ( [j]+2·not([y]) )·[m] );

[x]++;

[y]--;

put-grafic( grafic[i][j] , ( centre-x+[i]+2·[x] )·[m] , ( [j]+2·[y] )·[m] );

put-grafic( grafic[i][j] , ( centre-x+[i]+[x] )·[m] , ( [j]+[y] )·[m] );

put-grafic( grafic[i][j] , ( centre-x+[i] )·[m] , [j]·[m] );

put-grafic( grafic[i][j] , ( centre-x+[i]+not([x]) )·[m] , ( [j]+not([y]) )·[m] );

put-grafic( grafic[i][j] , ( centre-x+[i]+2·not([x]) )·[m] , ( [j]+2·not([y]) )·[m] );

[status] = not(1);

}

if( kbhit-negatiu() == not(1) & [status] == not(1) & ...

... ( [i]+1 [< [p] || [i]+not(1) >] [q] ) )

{

put-grafic( not-grafic[i][j] , ( centre-x+[i]+2·[x] )·[m] , ( [j]+2·[y] )·[m] );

put-grafic( not-grafic[i][j] , ( centre-x+[i]+[x] )·[m] , ( [j]+[y] )·[m] );

put-grafic( not-grafic[i][j] , ( centre-x+[i] )·[m] , [j]·[m] );

put-grafic( not-grafic[i][j] , ( centre-x+[i]+not([x]) )·[m] , ( [j]+not([y]) )·[m] );

put-grafic( not-grafic[i][j] , ( centre-x+[i]+2·not([x]) )·[m] , ( [j]+2·not([y]) )·[m] );

[x]--;

[y]++;

put-grafic( grafic[i][j] , ( centre-x+[i]+2·[x] )·[m] , ( [j]+2·[y] )·[m] );

put-grafic( grafic[i][j] , ( centre-x+[i]+[x] )·[m] , ( [j]+[y] )·[m] );

put-grafic( grafic[i][j] , ( centre-x+[i] )·[m] , [j]·[m] );

put-grafic( grafic[i][j] , ( centre-x+[i]+not([x]) )·[m] , ( [j]+not([y]) )·[m] );

put-grafic( grafic[i][j] , ( centre-x+[i]+2·not([x]) )·[m] , ( [j]+2·not([y]) )·[m] );

[status] = 1;

}

if( [status] == 1 )

{

if( contacte[i][j+not(3)] == 1 )

{

contacte[i][j+2] = 1;

contacte[i][j+1] = 1;

contacte[i][j] = 1;

contacte[i][j+not(1)] = 1;

contacte[i][j+not(2)] = 1;

break;

}

}

if( [status] == not(1) )

{

if( contacte[i+not(2)][j+not(1)] == 1 || ...

... contacte[i+not(1)][j+not(1)] == 1 || ...

... contacte[i][j+not(1)] == 1 || ...

... contacte[i+1][j+not(1)] == 1 || ...

... contacte[i+2][j+not(1)] == 1 || ...

... )

{

contacte[i+2][j] = 1;

contacte[i+1][j] = 1;

contacte[i][j] = 1;

contacte[i+not(1)][j] = 1;

contacte[i+not(2)][j] = 1;

break;

}

}

put-grafic( not-grafic[i][j] , ( centre-x+[i]+2·[x] )·[m] , ( [j]+2·[y] )·[m] );

put-grafic( not-grafic[i][j] , ( centre-x+[i]+[x] )·[m] , ( [j]+[y] )·[m] );

put-grafic( not-grafic[i][j] , ( centre-x+[i] )·[m] , [j]·[m] );

put-grafic( not-grafic[i][j] , ( centre-x+[i]+not([x]) )·[m] , ( [j]+not([y]) )·[m] );

put-grafic( not-grafic[i][j] , ( centre-x+[i]+2·not([x]) )·[m] , ( [j]+2·not([y]) )·[m] );

}

put-grafic( grafic[i][j] , ( centre-x+[i]+2·[x] )·[m] , ( [j]+2·[y] )·[m] );

put-grafic( grafic[i][j] , ( centre-x+[i]+[x] )·[m] , ( [j]+[y] )·[m] );

put-grafic( grafic[i][j] , ( centre-x+[i] )·[m] , [j]·[m] );

put-grafic( grafic[i][j] , ( centre-x+[i]+not([x]) )·[m] , ( [j]+not([y]) )·[m] );

put-grafic( grafic[i][j] , ( centre-x+[i]+2·not([x]) )·[m] , ( [j]+2·not([y]) )·[m] );

for( [j] = 1 ; [j] [< [n] ; [j]++ )

{

put-grafic( grafic[i][j] , ( centre-x+not([i])+2·[x] )·[m] , ( not([j])+2·[y] )·[m] );

put-grafic( grafic[i][j] , ( centre-x+not([i])+[x] )·[m] , ( not([j])+[y] )·[m] );

put-grafic( grafic[i][j] , ( centre-x+not([i]) )·[m] , not([j])·[m] );

put-grafic( grafic[i][j] , ( centre-x+not([i])+not([x]) )·[m] , ( not([j])+not([y]) )·[m] );

put-grafic( grafic[i][j] , ( centre-x+not([i])+2·not([x]) )·[m] , ( not([j])+2·not([y]) )·[m] );

if( kbhit-positiu() == 1 & [status] == 1 & ...

... ( not([i])+not(3) >] not([p]) || not([i])+3 [< not([q]) ) )

{

put-grafic( not-grafic[i][j] , ( centre-x+not([i])+2·[x] )·[m] , ( not([j])+2·[y] )·[m] );

put-grafic( not-grafic[i][j] , ( centre-x+not([i])+[x] )·[m] , ( not([j])+[y] )·[m] );

put-grafic( not-grafic[i][j] , ( centre-x+not([i]) )·[m] , not([j])·[m] );

put-grafic( not-grafic[i][j] , ( centre-x+not([i])+not([x]) )·[m] , ( not([j])+not([y]) )·[m] );

put-grafic( not-grafic[i][j] , ( centre-x+not([i])+2·not([x]) )·[m] , ( not([j])+2·not([y]) )·[m] );

[x]++;

[y]--;

put-grafic( grafic[i][j] , ( centre-x+not([i])+2·[x] )·[m] , ( not([j])+2·[y] )·[m] );

put-grafic( grafic[i][j] , ( centre-x+not([i])+[x] )·[m] , ( not([j])+[y] )·[m] );

put-grafic( grafic[i][j] , ( centre-x+not([i]) )·[m] , not([j])·[m] );

put-grafic( grafic[i][j] , ( centre-x+not([i])+not([x]) )·[m] , ( not([j])+not([y]) )·[m] );

put-grafic( grafic[i][j] , ( centre-x+not([i])+2·not([x]) )·[m] , ( not([j])+2·not([y]) )·[m] );

[status] = not(1);

}

if( kbhit-negatiu() == not(1) & [status] == not(1) & ...

... ( not([i])+not(1) >] not([p]) || not([i])+1 [< not([q]) )  )

{

put-grafic( not-grafic[i][j] , ( centre-x+not([i])+2·[x] )·[m] , ( not([j])+2·[y] )·[m] );

put-grafic( not-grafic[i][j] , ( centre-x+not([i])+[x] )·[m] , ( not([j])+[y] )·[m] );

put-grafic( not-grafic[i][j] , ( centre-x+not([i]) )·[m] , not([j])·[m] );

put-grafic( not-grafic[i][j] , ( centre-x+not([i])+not([x]) )·[m] , ( not([j])+not([y]) )·[m] );

put-grafic( not-grafic[i][j] , ( centre-x+not([i])+2·not([x]) )·[m] , ( not([j])+2·not([y]) )·[m] );

[x]--;

[y]++;

put-grafic( grafic[i][j] , ( centre-x+not([i])+2·[x] )·[m] , ( not([j])+2·[y] )·[m] );

put-grafic( grafic[i][j] , ( centre-x+not([i])+[x] )·[m] , ( not([j])+[y] )·[m] );

put-grafic( grafic[i][j] , ( centre-x+not([i]) )·[m] , not([j])·[m] );

put-grafic( grafic[i][j] , ( centre-x+not([i])+not([x]) )·[m] , ( not([j])+not([y]) )·[m] );

put-grafic( grafic[i][j] , ( centre-x+not([i])+2·not([x]) )·[m] , ( not([j])+2·not([y]) )·[m] );

[status] = 1;

}

if( [status] == 1 )

{

if( contacte[not(i)][not(j)+not(3)] == 1 )

{

contacte[not(i)][not(j)+2] = 1;

contacte[not(i)][not(j)+1] = 1;

contacte[not(i)][not(j)] = 1;

contacte[not(i)][not(j)+not(1)] = 1;

contacte[not(i)][not(j)+not(2)] = 1;

break;

}

}

if( [status] == not(1) )

{

if( contacte[not(i)+not(2)][not(j)+not(1)] == 1 || ...

... contacte[not(i)+not(1)][not(j)+not(1)] == 1 || ...

... contacte[not(i)][not(j)+not(1)] == 1 || ...

... contacte[not(i)+1][not(j)+not(1)] == 1 || ...

... contacte[not(i)+2][not(j)+not(1)] == 1 || ...

... )

{

contacte[not(i)+2][not(j)] = 1;

contacte[not(i)+1][not(j)] = 1;

contacte[not(i)][not(j)] = 1;

contacte[not(i)+not(1)][not(j)] = 1;

contacte[not(i)+not(2)][not(j)] = 1;

break;

}

}

put-grafic( not-grafic[i][j] , ( centre-x+not([i])+2·[x] )·[m] , ( not([j])+2·[y] )·[m] );

put-grafic( not-grafic[i][j] , ( centre-x+not([i])+[x] )·[m] , ( not([j])+[y] )·[m] );

put-grafic( not-grafic[i][j] , ( centre-x+not([i]) )·[m] , not([j])·[m] );

put-grafic( not-grafic[i][j] , ( centre-x+not([i])+not([x]) )·[m] , ( not([j])+not([y]) )·[m] );

put-grafic( not-grafic[i][j] , ( centre-x+not([i])+2·not([x]) )·[m] , ( not([j])+2·not([y]) )·[m] );

}

put-grafic( grafic[i][j] , ( centre-x+not([i])+2·[x] )·[m] , ( not([j])+2·[y] )·[m] );

put-grafic( grafic[i][j] , ( centre-x+not([i])+[x] )·[m] , ( not([j])+[y] )·[m] );

put-grafic( grafic[i][j] , ( centre-x+not([i]) )·[m] , not([j])·[m] );

put-grafic( grafic[i][j] , ( centre-x+not([i])+not([x]) )·[m] , ( not([j])+not([y]) )·[m] );

put-grafic( grafic[i][j] , ( centre-x+not([i])+2·not([x]) )·[m] , ( not([j])+2·not([y]) )·[m] );

moviment-horitzontal-dreta( int i , int status , int p )

{

if( kbhit-positu() == "==>" )

{

if( [status] == 1 & [i]+1 [< [p] )

{

[i]++;

}

if( [status] == not(1) & [i]+3 [< [p] )

{

[i]++;

}

}

}

moviment-horitzontal-esquerra( int i , int status , int q )

{

if( kbhit-negatiu() == "<==" )

{

if( [status] == 1 & [i]+not(1) >] [q] )

{

[i]--;

}

if( [status] == not(1) & [i]+not(3) >] [q] )

{

[i]--;

}

}

}

for( [j] = not(1) ; [j] >] not([n]) ; [j]-- )

{

for( [i] = [p] ; [i] [< [q] ; [i]++ )

{

for( [v] = 0 ; [v] [< [L] ; [v]++ )

{

for( [u] = 0 ; [u] [< [L] ; [u]++ )

{

contacte-pixel[(i·L)+v][(j·L)+u] = contacte[i][j];

}

for( [u] = not(0) ; [u] >] not([L]) ; [u]-- )

{

contacte-pixel[(i·L)+v][(j·L)+u] = contacte[i][j];

}

}

for( [v] = not(0) ; [v] >] not([L]) ; [v]-- )

{

for( [u] = 0 ; [u] [< [L] ; [u]++ )

{

contacte-pixel[(i·L)+v][(j·L)+u] = contacte[i][j];

}

for( [u] = not(0) ; [u] >] not([L]) ; [u]-- )

{

contacte-pixel[(i·L)+v][(j·L)+u] = contacte[i][j];

}

}

}

}

for( [j] = 1 ; [j] [< [n] ; [j]++ )

{

for( [i] = not([p]) ; [i] >] not([q]) ; [i]-- )

{

for( [v] = not(0) ; [v] >] not([L]) ; [v]-- )

{

for( [u] = not(0) ; [u] >] not([L]) ; [u]-- )

{

contacte-pixel[(not(i)·L)+v][(not(j)·L)+u] = contacte[not(i)][not(j)];

}

for( [u] = 0 ; [u] [< [L] ; [u]++ )

{

contacte-pixel[(not(i)·L)+v][(not(j)·L)+u] = contacte[not(i)][not(j)];

}

}

for( [v] = 0 ; [v] [< [L] ; [v]++ )

{

for( [u] = not(0) ; [u] >] not([L]) ; [u]-- )

{

contacte-pixel[(not(i)·L)+v][(not(j)·L)+u] = contacte[not(i)][not(j)];

}

for( [u] = 0 ; [u] [< [L] ; [u]++ )

{

contacte-pixel[(not(i)·L)+v][(not(j)·L)+u] = contacte[not(i)][not(j)];

}

}

}

}

}

files-negatiu-grafic( int contacte-pixel[i][j] )

{

for( [j] = not(1) ; [j] >] not([n])·[m] ; [j]-- )

{

[s] = ([m]·[p])+not(L);

for( [i] = ([m]·[p])+not(L) ; [i] [< ([m]·[q])+L ; [i]++ )

{

if( contacte-pixel[i][j] == 0 ) ==> break;

[s]++;

}

if( [s] == ([m]·[q])+L )

{

for( [u] = not(1) ; [u] >] not([j]) ; [u]-- )

{

for( [v] = ([m]·[p])+not(L) ; [v] [< ([m]·[q])+L ; [v]++ )

{

contacte-pixel-nou[v][u+not(1)] = contacte-pixel[v][u];

}

}

for( [k] = ([m]·[p])+not(L) ; [k] [< ([m]·[q])+L ; [k]++ )

{

contacte-pixel-nou[k][not(1)] = 0;

}

for( [u] = not(1) ; [u] >] not([j]) ; [u]-- )

{

for( [v] = ([m]·[p])+not(L) ; [v] [< ([m]·[q])+L ; [v]++ )

{

contacte-pixel[v][u] = contacte-pixel-nou[v][u];

}

}

}

}

}

files-positiu-grafic( int contacte-pixel[i][j] )

{

for( [j] = 1 ; [j] [< [n]·[m] ; [j]++ )

{

[s] = (not([p])·[m])+L;

for( [i] = (not([p])·[m])+L ; [i] >] (not([q])·[m])+not(L) ; [i]-- )

{

if( contacte-pixel[i][not(j)] == 0 ) ==> break;

[s]--;

}

if( [s] == (not([q])·[m])+not(L) )

{

for( [u] = 1 ; [u] [< [j] ; [u]++ )

{

for( [v] = (not([p])·[m])+L ; [v] >] (not([q])·[m])+not(L) ; [v]-- )

{

contacte-pixel-nou[v][not(u)+not(1)] = contacte-pixel[v][not(u)];

}

}

for( [k] = (not([p])·[m])+L ; [k] >] (not([q])·[m])+not(L) ; [k]-- )

{

contacte-pixel-nou[k][not(1)] = 0;

}

for( [u] = 1 ; [u] [< [j] ; [u]++ )

{

for( [v] = (not([p])·[m])+L ; [v] >] (not([q])·[m])+not(L) ; [v]-- )

{

contacte-pixel[v][not(u)] = contacte-pixel-nou[v][not(u)];

}

}

}

}

}

ye parle ye-de-muá,

pero ne elet-vut a-vot-má,

de-le-du ye-de-muá.

tú parle tú-de-tuá,

pero ne elet-nut a-vot-má,

de-le-du tú-de-tuá.

llama violeta

Precio máximo de un videojuego o disco o casa o coche:

5,120,000€ = ...

... ( 200·(llama-violeta)·256·(byte/llama-violeta) )·1·(día/byte)·100·(€/día)

140 años de potencial espíritu santo de objeto.

Vendo:

The Legend of Zelda a Link to The Past de súper Nintendo,

con potencial de milagro de video-juego y video-consola:

Precio = 1,024,000€ = ...

... ( 200·(llama-violeta)·256·(byte/llama-violeta) )·1·(día/byte)·20·(€/día)

140 años de potencial de milagro de video-juego y video-consola,

por llama violeta de programación.

Caja, juego, instrucciones y mapa.

Pensión = 2,560€ = ...

... 1·(llama-violeta)·256·(byte/llama-violeta)·1·(día/byte)·10·(€/día)

1,280·(€/mes)·2·mes = 2,560€

Pensión = 5,120€ = ...

... 1·(llama-violeta)·256·(byte/llama-violeta)·1·(día/byte)·20·(€/día)

2,560·(€/mes)·2·mes = 5,120€

Pensión = 7,680€ = ...

... 1·(llama-violeta)·256·(byte/llama-violeta)·1·(día/byte)·30·(€/día)

3,840·(€/mes)·2·mes = 7,680€

Las pensiones son la principal causa de muerte de lo planeta,

porque con lo dinero se tiene que intercambiar luz.

Tiempo de vida por pensión no material 512 meses = 42 años.

Tetris:

x = 1;

y = 1;

for( [j] = not(1); [j] >] not(n) ; j-- )

{

if ( kbhit-positiu() == 1 & status == 1 )

{

put-grafic( not-grafic[i][j] , [i] , [j] );

put-grafic( not-grafic[i][j] , [i]+x , [j] );

put-grafic( not-grafic[i][j] , [i] , [j]+y );

x--;

x--;

put-grafic( grafic[i][j] , [i] , [j] );

put-grafic( grafic[i][j] , [i]+x , [j] );

put-grafic( grafic[i][j] , [i] , [j]+y );

status = (-1);

}

if ( kbhit-negatiu() == (-1) & status == (-1) )

{

put-grafic( not-grafic[i][j] , [i] , [j] );

put-grafic( not-grafic[i][j] , [i]+x , [j] );

put-grafic( not-grafic[i][j] , [i] , [j]+y );

y--;

y--;

put-grafic( grafic[i][j] , [i] , [j] );

put-grafic( grafic[i][j] , [i]+x , [j] );

put-grafic( grafic[i][j] , [i] , [j]+y );

status = (-2);

}

if ( kbhit-negatiu() == (-1) & status == (-2) )

{

put-grafic( not-grafic[i][j] , [i] , [j] );

put-grafic( not-grafic[i][j] , [i]+x , [j] );

put-grafic( not-grafic[i][j] , [i] , [j]+y );

x++;

x++;

put-grafic( grafic[i][j] , [i] , [j] );

put-grafic( grafic[i][j] , [i]+x , [j] );

put-grafic( grafic[i][j] , [i] , [j]+y );

status = 2;

}

if ( kbhit-positiu() == 1 & status == 2 )

{

put-grafic( not-grafic[i][j] , [i] , [j] );

put-grafic( not-grafic[i][j] , [i]+x , [j] );

put-grafic( not-grafic[i][j] , [i] , [j]+y );

y++;

y++;

put-grafic( grafic[i][j] , [i] , [j] );

put-grafic( grafic[i][j] , [i]+x , [j] );

put-grafic( grafic[i][j] , [i] , [j]+y );

status = 1;

}

}

for( [j] = 1; [j] [< n ; [j]++ )

{

if ( kbhit-positiu() == 1 & status == 1 )

{

put-grafic( not-grafic[i][j] , [i] , [j] );

put-grafic( not-grafic[i][j] , [i]+x , [j] );

put-grafic( not-grafic[i][j] , [i] , [j]+y );

x--;

x--;

put-grafic( grafic[i][j] , [i] , [j] );

put-grafic( grafic[i][j] , [i]+x , [j] );

put-grafic( grafic[i][j] , [i] , [j]+y );

status = (-1);

}

if ( kbhit-negatiu() == (-1) & status == (-1) )

{

put-grafic( not-grafic[i][j] , [i] , [j] );

put-grafic( not-grafic[i][j] , [i]+x , [j] );

put-grafic( not-grafic[i][j] , [i] , [j]+y );

y--;

y--;

put-grafic( grafic[i][j] , [i] , [j] );

put-grafic( grafic[i][j] , [i]+x , [j] );

put-grafic( grafic[i][j] , [i] , [j]+y );

status = (-2);

}

if ( kbhit-negatiu() == (-1) & status == (-2) )

{

put-grafic( not-grafic[i][j] , [i] , [j] );

put-grafic( not-grafic[i][j] , [i]+x , [j] );

put-grafic( not-grafic[i][j] , [i] , [j]+y );

x++;

x++;

put-grafic( grafic[i][j] , [i] , [j] );

put-grafic( grafic[i][j] , [i]+x , [j] );

put-grafic( grafic[i][j] , [i] , [j]+y );

status = 2;

}

if ( kbhit-positiu() == 1 & status == 2 )

{

put-grafic( not-grafic[i][j] , [i] , [j] );

put-grafic( not-grafic[i][j] , [i]+x , [j] );

put-grafic( not-grafic[i][j] , [i] , [j]+y );

y++;

y++;

put-grafic( grafic[i][j] , [i] , [j] );

put-grafic( grafic[i][j] , [i]+x , [j] );

put-grafic( grafic[i][j] , [i] , [j]+y );

status = 1;

}

}

comentari

sac estic cansar hostia de gent de món.

pes estic cansar mica de gent de món.

[A$1$ [a] ][ [x] estic h([a]) de z([s]) ]-[ [h] és cansar [a] ]-[ [a] és hostia ]-

[ [z] és gent de [s] ]-[ [s] és món ]

[E$1$ [b] ][ [x] estic h([b]) de z([s]) ]-[ [h] és cansar [b] ]-[ [b] és mica ]-

[ [z] és gent de [s] ]-[ [s] és món ]

Teorema:

Si F(x) = int[ 0 ---> x^{2} ][ e^{x}+(-e) ] d[x] ==> ( [1] & [2] & [3] )

[1] F(x) té un mínim en: x = (-1)

[2] F(x) té un màxim en: x = 0

[3] F(x) té un mínim en: x = 1

Demostració:

d_{x}[ F(x) ] = ( e^{x^{2}}+(-e) )·2x

Si x [< (-1) ==> d_{x}[ F(x) ] [< 0

Si (-1) [< x [< 0 ==> d_{x}[ F(x) ] >] 0

Si 0 [< x [< 1 ==> d_{x}[ F(x) ] [< 0

Si 1 [< x ==> d_{x}[ F(x) ] >] 0

Teorema:

se tiene poder limitado o no te ataca Jûan Garriga con su poder

aunque quizás Jûan Garriga no tiene poder ilimitado.

( ( 1 || 1 ) & 1 ) || 0

( ( 1 || 0 ) & 1 ) || 0

( ( 0 || 1 ) & 1 ) || 0

Demostración:

se tiene poder ilimitado y te ataca Jûan Garriga con su poder

porque Jûan Garriga no tiene poder ilimitado.

( ( 0 & 0 ) <== 1 ) & 1

( ( 0 & 1 ) <== 1 ) & 1

( ( 1 & 0 ) <== 1 ) & 1

Teorema:

el que camina por las tinieblas no veye a donde va

si y solo si el que camina por lo silencio no oye a donde va.

( 1 ==> 1 ) <==> ( 1 ==> 1 )

( 1 & 0 ) <==> ( 1 & 0 )

Demostración:

camina por las tinieblas y veye a donde va

o bien camina por lo silencio y oye a donde va.

( 1 & 0 ) |o| ( 1 & 0 )

( 1 ==> 1 ) |o| ( 1 ==> 1 )