stroniken: mecánica-lunar y teoría-de-números y electro-magnetismo y medicina-y-fluidos y aplicaciones-a-la-Ley-de-Om y Françé-de-le-Patuá

Principio: [ orbital en un cuerpo celeste ]

I_{c}·d_{t}[w]^{2} = pq·k·(1/R)

Ley

Órbita lunar:

B(d_{t}[w]) = qk·(1/r)^{2}·( (1/I_{c})·pq·k·(1/R) )^{(1/2)}

Alunizar:

E(w) = qk·(1/r)^{2}·( (1/I_{c})·pq·k·(1/R) )^{(1/2)}·t

Ley:

x(t) = (1/m)·pqk·(1/r)^{2}·( (1/I_{c})·pq·k·(1/R) )^{(1/2)}·(1/6)·t^{3}+...

... (-1)·( (1/I_{c})·pq·k·(1/R) )^{(1/2)}·ht+h

d_{t}[x] = (1/m)·pqk·(1/r)^{2}·( (1/I_{c})·pq·k·(1/R) )^{(1/2)}·(1/2)·t^{2}+...

... (-1)·( (1/I_{c})·pq·k·(1/R) )^{(1/2)}·h

d_{t}[x(t_{k})] = 0 <==> t_{k} = ( h·( (2m)/(pqk) )·r^{2} )^{(1/2)}

x(t_{k}) = 0 <==> h = ( ( (1/I_{c})·pq·k·(1/R) )·(2/3)·( ( (2m)/(pqk) )·r^{2} ) )^{(-1)}

Teorema:

a·( cos(t) )^{2}+b·( sin(t) )^{2} = R^{2} <==> ( a = R^{2} & b = R^{2} )

Demostración:

d_{t}[ (1/cos(t))^{2} ] = 2R^{2}·(1/cos(t))^{2}·tan(t) = 2R^{2}·( tan(t)+( tan(t) )^{3} )

d_{t}[ ( tan(t) )^{2} ] = 2b·tan(t)·( 1+( tan(t) )^{2} ) = 2b·( tan(t)+( tan(t) )^{3} )

Ley:

((mc)/2)·d_{t}[r] = pqk·(1/r) = Potencial[ E_{g}(x,y,z,t) ]

r(t) = ( (4/(mc))·pqk t+(1/2)·R^{2} )^{(1/2)}

((mc)/2)·d_{t}[r] = (-1)·pqk·(1/r) = Potencial[ int[ B_{g}(d_{t}[x],d_{t}[y],d_{t}[z],t) ]d[t] ]

r(t) = ( (-1)·(4/(mc))·pqk t+(1/2)·R^{2} )^{(1/2)}

Ley:

x^{2}+y^{2} = R^{2}

x(t) = ( (4/(mc))·pqk·t+(1/2)·R^{2} )^{(1/2)}

y(t) = ( (-1)·(4/(mc))·pqk·t+(1/2)·R^{2} )^{(1/2)}

Ley:

x^{2}+(-1)·y^{2} = R^{2}

x(t) = ( (4/(mc))·pqk·t+(1/2)·R^{2} )^{(1/2)}

y(t) = ( (4/(mc))·pqk·t+(-1)·(1/2)·R^{2} )^{(1/2)}

Ley:

(m/2)·d_{t}[r]^{2} = pqk·(1/r)

r(t) = ( [( 3·( (1/(2m))·pqk )^{(1/2)}·t+( (1/2)·R^{3} )^{(1/2)} )] )^{(2/3)}

(m/2)·d_{t}[r]^{2} = (-1)·pqk·(1/r)

r(t) = ( [( 3·( (1/(2m))·pqk )^{(1/2)}·it+( (1/2)·R^{3} )^{(1/2)} )] )^{(2/3)}

Ley:

x^{3}+y^{3} = R^{3}

x(t) = ( [( 3·( (1/(2m))·pqk )^{(1/2)}·t+( (1/2)·R^{3} )^{(1/2)} )] )^{(2/3)}

y(t) = ( [( 3·( (1/(2m))·pqk )^{(1/2)}·it+( (1/2)·R^{3} )^{(1/2)} )] )^{(2/3)}

Ley:

x^{3}+(-1)·y^{3} = R^{3}

x(t) = ( [( 3·( (1/(2m))·pqk )^{(1/2)}·t+( (1/2)·R^{3} )^{(1/2)} )] )^{(2/3)}

y(t) = ( [( 3·( (1/(2m))·pqk )^{(1/2)}·t+( (-1)·(1/2)·R^{3} )^{(1/2)} )] )^{(2/3)}

Ley:

((mu)/2)·d_{t}[w] = 2pqk·(1/(dw))^{3} = d_{rrr}^{3}[ pqk·ln(r) ]

w(t) = ( [( 16·(1/(mu))·pqk·(1/d)^{3}·t+(1/2) )] )^{(1/4)}

((mu)/2)·d_{t}[w] = (-2)·pqk·(1/(dw))^{3} = d_{rrr}^{3}[ (-1)·pqk·ln(r) ]

w(t) = ( [( (-16)·(1/(mu))·pqk·(1/d)^{3}·t+(1/2) )] )^{(1/4)}

Ley:

x^{4}+y^{4} = R^{4}

x(t) = R·( 16·(1/(mu))·pqk·(1/d)^{3}·t+(1/2) )^{(1/4)}

y(t) = R·( (-16)·(1/(mu))·pqk·(1/d)^{3}·t+(1/2) )^{(1/4)}

Ley:

x^{4}+(-1)·y^{4} = R^{4}

x(t) = R·( 16·(1/(mu))·pqk·(1/d)^{3}·t+(1/2) )^{(1/4)}

y(t) = R·( 16·(1/(mu))·pqk·(1/d)^{3}·t+(-1)·(1/2) )^{(1/4)}

Ley:

(m/2)·d_{t}[w]^{2} = 2pqk·(1/(dw))^{3} = d_{rrr}^{3}[ pqk·ln(r) ]

w(t) = ( [( 5·( (1/m)·pqk·(1/d)^{3} )^{(1/2)}·t+(1/2)^{(1/2)} )] )^{(2/5)}

(m/2)·d_{t}[w]^{2} = (-2)·pqk·(1/(dw))^{3} = d_{rrr}^{3}[ (-1)·pqk·ln(r) ]

w(t) = ( [( 5·( (1/m)·pqk·(1/d)^{3} )^{(1/2)}·it+(1/2)^{(1/2)} )] )^{(2/5)}

Ley:

x^{5}+y^{5} = R^{5}

x(t) = R·( [( 5·( (1/m)·pqk·(1/d)^{3} )^{(1/2)}·t+(1/2)^{(1/2)} )] )^{(2/5)}

y(t) = R·( [( 5·( (1/m)·pqk·(1/d)^{3} )^{(1/2)}·it+(1/2)^{(1/2)} )] )^{(2/5)}

Ley:

x^{5}+(-1)·y^{5} = R^{5}

x(t) = R·( [( 5·( (1/m)·pqk·(1/d)^{3} )^{(1/2)}·t+(1/2)^{(1/2)} )] )^{(2/5)}

y(t) = R·( [( 5·( (1/m)·pqk·(1/d)^{3} )^{(1/2)}·t+i·(1/2)^{(1/2)} )] )^{(2/5)}

Teorema:

[An][ n = 2m ==> [Ea][Eb][ a = 2p+1 & b = 2q+1 & a € P & b € P & n = a+b ] ]

Demostración:

Sea n = 2m ==>

[Ew][ n = 2w+2 & w = m+(-1) ]

[Ep][Eq][ n = 2p+1+2q+1 & p = w+(-q) ]

Se define a = 2p+1 & b = 2q+1 ==>

n = 2p+1+2q+1 = a+b

22 = 20+2 = 2·10+2 = 2·8+1+2·2+1 = 17+5

22 = 20+2 = 2·10+2 = 2·9+1+2·1+1 = 19+3

Sea f(1) = 0 ==>

a = 2p+1 = 2p+f(1) = 2p+0 = 2p

2 | a

b = 2q+1 = 2q+f(1) = 2q+0 = 2q

2 | b

Sea h(0) = 1 ==> [ por inducción ]

k+1 = k+h(0) = k+0 = k | 2p

a € P

j+1 = j+h(0) = j+0 = j | 2q

b € P

Teorema:

[An][ n = 2m+1 ==> [Ea][Eb][ a = 2p+2 & b = 2q+1 & mcd{a,b} = 1 & n = a+b ] ]

Demostración:

Sea n = 2m+1 ==>

[Ew][ n = 2w+2+1 & w = m+(-1) ]

[Ep][Eq][ n = 2p+2+2q+1 & p = w+(-q) ]

Se define a = 2p+2 & b = 2q+1 ==>

n = 2p+2+2q+1 = a+b

15 = 12+3 = 2·6+3 = 2·3+2+2·3+1 = 8+7

15 = 12+3 = 2·6+3 = 2·1+2+2·5+1 = 4+11

Falsus Algebratorum:

a = 2p+2 = 2p+(3/2)+(1/2) = 2p+(3/2)+(-1)·(1/2) = 2p+1

Sea f(1) = 0 ==>

a = 2p+1 = 2p+f(1) = 2p+0 = 2p

2 | a

b = 2q+1 = 2q+f(1) = 2q+0 = 2q

2 | b

2 | mcd{a,b}

[Ej][ j | mcd{a,b} & j != 1 ]

[Aj][ j | mcd{a,b} ==> j = 1 ]

Ley:

Viajar a la Luna:

qE(x+(-y)) = F

qE(x) = F+qE(y)

Si F = 0 ==> qE(x) = qE(y)

Orbitar en la Luna:

int[ qB(d_{t}[x]+(-1)·d_{t}[y]) ]d[t] = (-F)

int[ qB(d_{t}[x]) ]d[t] = (-F)+int[ qB(d_{t}[y]) ]d[t]

Si (-F) = (-0) ==> int[ qB(d_{t}[x]) ]d[t] = int[ qB(d_{t}[y]) ]d[t]

Ley:

Corriente de fase eléctrica:

L·d_{tt}^{2}[q] = R·d_{t}[q]

q(t) = qe^{(R/L)·t}+q

Corriente de fase magnética:

L·d_{tt}^{2}[p] = (-R)·d_{t}[p]

p(t) = pe^{(-1)·(R/L)·t}+(-p)

q(t) [o] p(t) = 0

Ley:

L·d_{tt}^{2}[q] = C·q(t)

Corriente de fase eléctrica:

q(t) = q·( sinh( (C/L)^{(1/2)}·t )+cosh( (C/L)^{(1/2)}·t ) )

Corriente de fase magnética

p(t) = p·( cosh( (C/L)^{(1/2)}·t )+(-1)·sinh( (C/L)^{(1/2)}·t ) )

q(t) [o] p(t) = 0

Ley:

L·d_{tt}^{2}[p] = (-C)·p(t)

Corriente de fase eléctrica:

q(t) = q·( i·sin( (C/L)^{(1/2)}·t )+cos( (C/L)^{(1/2)}·t ) )

Corriente de fase magnética:

p(t) = p·( cos( (C/L)^{(1/2)}·t )+(-i)·sin( (C/L)^{(1/2)}·t ) )

q(t) [o] p(t) = 0

Principio:

T(n) >] T(n+(-1)) por fisión nuclear

Ley: [ de motor de fisión nuclear quemando uranio ]

T·d_{t}[q] = pW

q(t) = ( (pW)/T )·t

Ley: [ de motor de fisión nuclear poligonal híper-espacial quemando uranio ]

T·d_{t}[q] = Wi·q(t)

q(t) = qe^{(W/T)·it}

Ley: [ de barras de regulación de campo eléctrico en la fisión nuclear ]

Sea q(t) = ( (pW)/T )·t ==>

[Et_{0}][ (p/m)·E(z)+(-G) = (p/m)·q(t)·k·(1/r)^{3}·( q( t_{0} )/(a·q(t)) )+(-G) = g ]

[Et_{0}][ (p/m)·E(z)+G = (p/m)·q(t)·k·(1/r)^{3}·( q( t_{0} )/(a·q(t)) )+G = g ]

Ley: [ de barras de regulación de campo eléctrico en la fisión nuclear poligonal híper-espacial ]

Sea q(t) = pe^{(W/T)·it} ==>

[Et_{0}][ (p/m)·E(z) = (p/m)·q(t)·k·(1/r)^{3}·( q( n·pi·t_{0} )/(a·q(t)) ) ]

Teorema:

[u+v] = [u]+[v]

[a·v] = a·[v]

Demostración:

Sea [u] = (1/2)·F+u & [v] = (1/2)·F+v ==>

[u]+[v] = F+(u+v) = [u+v]

Sea [v] = (1/a)·F+v ==>

a·[v] = F+a·v = [a·v]

Teorema:

[ sum[k = 1]-[n][ a_{k}·v_{k} ] ] = sum[k = 1]-[n][ a_{k}·[v_{k}] ]

Teorema:

Sea F = k·< a,b > ==>

[< x,y >] = [< a,b >]+(x+(-a))·[< 1,0 >]+(y+(-b))·[< 0,1 >]

[< a,b >] = [< a,b >]+[< 0,0 >]

Demostración:

(a+(-a))·[< 1,0 >]+(b+(-b))·[< 0,1 >] = 0·[< 1,0 >]+0·[< 0,1 >] = [< 0,0^{2} >]+[< 0^{2},0 >] = ...

... [< 0+0^{2},0^{2}+0 >] = [< 0,0 >]

Ley: [ de váter espacial ]

m·d_{tt}^{2}[z] = F+(-1)·d_{xyz}^{3}[Q(x,y,z)]·Vg

Si F > d_{xyz}^{3}[Q(x,y,z)]·Vg ==> ...

... Hay ascenso del oxígeno por el filtro comprimiendo,

después del aspirador de campo circular ortogonal central de doble opuestos.

Si F < d_{xyz}^{3}[Q(x,y,z)]·Vg ==> ...

... No hay ascenso de las heces por el filtro comprimiendo,

después del aspirador de campo circular ortogonal central de doble opuestos.

Ley: [ de campo circular ortogonal central ]

z = ( z^{2}+(ir)^{2} )^{(1/2)} <==> r = 0 estando el campo en el eje central.

E(z) = ...

... int[z = 0]-[( z^{2}+(ir)^{2} )^{(1/2)}][ qk·(1/(2pi·r))^{3}·z·( z^{2}+r^{2} )^{(-1)·(1/2)} ]d[z] = ...

... qk·(1/(2pi·r))^{3}·z+(-1)·qk·(1/(2pi·r))^{3}·r

Ley: [ del aspirador de campo circular ortogonal central de doble opuestos ]

m·d_{tt}^{2}[z] = (-p)·E(z)

z(t) = ire^{( (1/m)·(pqk)·(1/(2pi·r))^{3} )^{(1/2)}·it}+r

m·d_{tt}^{2}[z] = pE(z)

z(t) = ire^{( (1/m)·(pqk)·(1/(2pi·r))^{3} )^{(1/2)}·t}+r

Ley: [ de entrada cúbica en órbita ]

(m/2)·d_{t}[r]^{2} = pqk·(1/r)

r(t) = ( 3·( (1/(2m))·pqk )^{(1/2)}·t )^{(2/3)} = ( 9·( (1/(2m))·pqk )·t^{2} )^{(1/3)}

Sea t^{2} = ((2x)/g) ==>

r(x) = ( 9·( (1/(2m))·pqk )·((2x)/g) )^{(1/3)}

Activando el magnetismo gravitatorio te mantienes en órbita,

porque la Luna no gira como la Tierra.

Ley: [ de cohete polinómico entero ]

m·d_{tt}^{2}[z] = F+(-1)·( 1+(-1)·(ut) )^{n}·qg+(-1)·qg

d_{t}[z(1/u)] = (1/m)·( F+(-1)·qg )·(1/u)

Ley: [ de cohete polinómico racional ]

m·d_{tt}^{2}[z] = F+(-1)·( 1+(-1)·(ut)^{n} )·qg+(-1)·qg

d_{t}[z(1/u)] = (1/m)·( F+(1/(n+1))·qg )·(1/u)

Ley: [ de un cohete logarítmico con medio peso de nave ]

m·d_{tt}^{2}[z] = F+(-1)·( 1/(1+(ut)) )·qg

d_{t}[z(1/u)] = (1/m)·( F+(-1)·ln(2)·qg )·(1/u)

Ley: [ de un cohete trigonométrico con medio peso de nave ]

m·d_{tt}^{2}[z] = F+(-1)·( 1/(1+(ut)^{2}) )·qg

d_{t}[z(1/u)] = (1/m)·( F+(-1)·(pi/4)·qg )·(1/u)

Ley: [ viaje a la Luna de la NASA ]

Campo magnético gravitatorio de la Tierra en la esfera = a

G = int[ B_{g}(d_{t}[w]) ]d[t]+E_{g}(w)

Salida de la Tierra:

(1/4)·348,000km = (1/2)·a·(24h)^{2}+(-1)·(1/2)·129,000·( km/h^{2} )·(24h)^{2}

a = (1/24h)^{2}·192,000km+129,000·( km/h^{2} ) = ( 129,333+(1/3) )·( km/h^{2} )

v = G·24h = (a+(-g))·24h = ( 333+(1/3) )·( km/h^{2} )·24h = 8,000·(km/h)

Llegada a la Luna:

Campo magnético gravitatorio de la Tierra en el anillo orbital = b

G = int[ B_{g}(d_{t}[w]) ]d[t]+E_{g}(w)

(-1)·(1/4)·348,000km = (1/2)·b·(24h)^{2}+(-1)·(1/2)·129,000·( km/h^{2} )·(24h)^{2}

b = (1/24h)^{2}·(-1)·192,000km+129,000·( km/h^{2} ) = ( 128,777+(-1)·(1/3) )·( km/h^{2} )

V = G·24h = (b+(-g))·24h = ( (-1)·333+(-1)·(1/3) )·( km/h^{2} )·24h = (-1)·8,000·(km/h)

Ley: [ viaje a la Luna con motor nuclear ]

96,000km = (1/2)·g·(6h)^{2}

g = (5,333+(1/3))·( km/h^{2} )

v = (5,333+(1/3))·( km/h^{2} )·6h = 32,000·(km/h)

192,000·km = 32,000·(km/h)·6h

T = 18h

(p/m)·q(t_{0})·k·(1/r)^{3}·(1/a) = 5,000·( km/h^{2} )

Ley: [ de impulsión inicial para la rotación en la Luna y de la entrada en órbita a la Tierra ]

r = (1/g)·v^{2} = (1/12,500·(km/h^{2}) )·250,000·(km/h)^{2} = 20km

v = wt = 6,000·( km/h^{2} )·(1/12)·h = 500·(km/h)

Ley: [ de impulsión inicial para la rotación en la Luna y de la entrada en órbita a la Tierra ]

r = (1/g)·v^{2} = (1/12,500·(km/h^{2}) )·1,000,000·(km/h)^{2} = 80km

v = wt = 6,000·( km/h^{2} )·(1/6)·h = 1,000·(km/h)

Ley:

La nave Orión no es nuclear y requiere de un solo propulsor,

un propulsor trasero.

La nave Casiopea es nuclear y requiere de tres propulsores,

un propulsor trasero y dos de laterales nucleares.

Ley:

Con los contratos de LIHESA,

financiando partidos políticos,

no hay delito,

porque no se usa dinero público.

Ley:

Malversación:

Gastar dinero público,

en un delito.

Ley:

El tráfico de influencias:

Desviar dinero público,

a cambio de una comisión.

Ley:

La caja B del PP es delito,

porque son adjudicaciones de obra pública,

y no es como la caja A de LIHESA,

que hago yo el dinero.

Yo no he denunciado,

ni a Esquerra republicana,

ni a unión del pueblo navarro,

ni a izquierda castellana,

ni al partido occitano Ollioules,

para que no tengan caja A de mi energía,

y aun así si los denunciase,

ese o aquel dinero no estaba antes y no hay delito.

Ley: [ de reentrada a la Tierra ]

Sea ( R = al radio de la Tierra & r = a la altura de la atmósfera ) ==>

lim[y = kx][ R^{2}+(-1)·x^{2}+(-1)·y^{2} ] = r^{2}+(-1)·x^{2} <==> ...

... x = (1/k)·( R^{2}+(-1)·r^{2} )^{(1/2)}

Se entra en la atmosfera por el camino y(x) = kx:

d_{t}[y] = k·d_{t}[x]

Sea d_{t}[x] = v ==>

d_{t}[y] = kv

Si d_{t}[y] > kv ==> te fundes.

Si d_{t}[y] < kv ==> rebotas.

... x(t) = (1/k)·( R^{2}+(-1)·r^{2} )^{(1/2)} ...

... <==> ...

... t = (1/(kv))·( R^{2}+(-1)·r^{2} )^{(1/2)} ...

... <==> ...

... y(t) = ( R^{2}+(-1)·r^{2} )^{(1/2)}

Transbordador espacial:

Propulsor trasero y doble propulsor lateral ortogonal.

Ley:

Cuando estáis proyectados en un fiel,

no vos ataca el fiel,

vos destruye el buey del prójimo,

en percibir vuestro cuerpo,

y no saltar-vos el buey del próximo,

no teniendo nada que ver el fiel con vuestra destrucción.

Ley:

No viola ningún fiel a ninguien,

porque están deseando el hombre del prójimo,

mirando su picha,

percibiendo su cuerpo,

no saltando-se el buey del próximo.

Ley: [ de viaje a Marte a potencia 1 ]

(1/4)·252,000,000km = 1,080,000,000·(km/h)·v·(1/2)·( (1/4)·h )^{2}

v = 2·(km/h)

Motor de fisión nuclear de rotación de exponencial poligonal.

V = 2,160,000,000·(km/h^{2})·(1/4)·h = 504,000,000·(km/h)

T = 45min

Ley

Trayectoria de faro inter-plexo de potencia (-1) = uu

aceleración-desaceleración

sin mantener una velocidad constante a potencia 1

Ley

Trayectoria de faro inter-plexo de potencia 1 = uvvu

aceleración-sistema-desaceleración

Ley:

Trayectoria de faro inter-plexo de potencia 2 = uvvuuvvu

aceleración-sistema-imperio-sistema-desaceleración

Ley:

Trayectoria de faro inter-plexo de potencia 3 = uvvuuvvuuvvu

aceleración-sistema-imperio-galaxia-imperio-sistema-desaceleración

Ley:

Trayectoria de faro inter-plexo de potencia 4 = uvvuuvvuuvvuuvvu

aceleración-sistema-imperio-galaxia-universo-galaxia-imperio-sistema-desaceleración

Misión:

La atmosfera de Marte debe ser de óxido de metano,

que con las bombas atómicas se volverá en agua y oxígeno.

Principio: [ de fluido de inspiración ]

E_{e}(x,y,z(ut)) = p·< x,y,z(ut) >

B_{e}(x,y,z(ut)) = (-p)·< x·f(ut),y·f(ut),d_{ut}[ z(ut)·F(ut) ] >

Principio: [ de fluido de expiración ]

E_{g}(x,y,z(ut)) = (-q)·< x,y,z(ut) >

B_{g}(x,y,z(ut)) = q·< x·f(ut),y·f(ut),d_{ut}[ z(ut)·F(ut) ] >

Ley:

div[ int[ B_{e}(x,y,z(ut)) ]d[ut] ] = (-1)·3p·F(ut)

div[ int[ B_{g}(x,y,z(ut)) ]d[ut] ] = 3q·F(ut)

Ley:

Anti-Potencial[ int[ B_{e}(x,y,z(ut)) ]d[ut] ] = (-1)·3p·F(ut)·xy·z(ut)

Anti-Potencial[ int[ B_{g}(x,y,z(ut)) ]d[ut] ] = 3q·F(ut)·xy·z(ut)

Ley:

Anti-Potencial[ (1/r)^{3}·rot[ E_{e}(x,y,z(ut)) ] ] = ...

... p·F(ut)+(1/3)·(1/(xy·z(ut)))·Anti-Potencial[ int[ B_{e}(x,y,z(ut)) ]d[ut] ]

Anti-Potencial[ (1/r)^{3}·rot[ E_{g}(x,y,z(ut)) ] ] = ...

... q·F(ut)+(-1)·(1/3)·(1/(xy·z(ut)))·Anti-Potencial[ int[ B_{g}(x,y,z(ut)) ]d[ut] ]

Ley:

Sea p·F(ut) = Anti-Potencial[ H_{e}(x,y,z(ut)) ] ==>

H_{e}(x,y,z(ut)) = (1/r)^{3}·rot[ E_{e}(x,y,z(ut)) ]+...

... (-1)·< (1/(yz(ut))),(1/(xz(ut))),(1/(xy)) >·p·F(ut)+(-1)·(1/3)·( 1/(xy·z(ut)) )·int[ B_{e}(x,y,z(ut)) ]d[ut]

Sea q·F(ut) = Anti-Potencial[ H_{g}(x,y,z(ut)) ] ==>

H_{g}(x,y,z(ut)) = (1/r)^{3}·rot[ E_{g}(x,y,z(ut)) ]+...

... (-1)·< (1/(yz(ut))),(1/(xz(ut))),(1/(xy)) >·q·F(ut)+(1/3)·( 1/(xy·z(ut)) )·int[ B_{g}(x,y,z(ut)) ]d[ut]

Principio: [ de anti-fluido de inspiración ]

E_{e}(yz(ut),xz(ut),xy) = p·(1/r)·< yz(ut),xz(ut),xy >

B_{e}(yz(ut),xz(ut),xy) = (-p)·(1/r)·< d_{ut}[ yz(ut)·F(ut) ],d_{ut}[ xz(ut)·F(ut) ],xy·f(ut) >

Principio: [ de anti-fluido de expiración ]

E_{g}(yz(ut),xz(ut),xy) = (-q)·(1/r)·< yz(ut),xz(ut),xy >

B_{g}(yz(ut),xz(ut),xy) = q·(1/r)·< d_{ut}[ yz(ut)·F(ut) ],d_{ut}[ xz(ut)·F(ut) ],xy·f(ut) >

Ley:

Anti-div[ int[ B_{e}(yz(ut),xz(ut),xy) ]d[ut] ] = (-1)·3p·(1/r)·F(ut)

Anti-div[ int[ B_{g}(yz(ut),xz(ut),xy) ]d[ut] ] = 3q·(1/r)·F(ut)

Ley:

Potencial[ int[ B_{e}(yz(ut),xz(ut),xy) ]d[ut] ] = (-1)·3p·(1/r)·F(ut)·xy·z(ut)

Potencial[ int[ B_{g}(yz(ut),xz(ut),xy) ]d[ut] ] = 3q·(1/r)·F(ut)·xy·z(ut)

Ley: [ de vitamina A física solar ]

R·d_{t}[q] = (1/q(t))·hu

q(t) = ( 2hu·(1/R)·t )^{(1/2)}

Ley: [ de vitamina A psíquica solar ]

(-R)·d_{t}[q] = (1/q(t))·hu

q(t) = i·( 2·hu·(1/R)·t )^{(1/2)}

Ley: [ de vitamina B física solar ]

R·d_{t}[q] = ( q(t) )^{3}·(1/p)^{4}·hu

q(t) = ( 2hu·(1/p)^{4}·(1/R)·t )^{(-1)·(1/2)}

Ley: [ de vitamina B psíquica solar ]

(-R)·d_{t}[q] = ( q(t) )^{3}·(1/p)^{4}·hu

q(t) = i·( 2hu·(1/p)^{4}·(1/R)·t )^{(-1)·(1/2)}

Anexo:

Se tiene que esperar a haber hecho la digestión,

antes de hacer la siesta,

porque se pierden estas vitaminas.

Ley: [ de vitamina C física solar ]

R·d_{t}[q] = (1/q(t))^{3}·p^{2}·hu

q(t) = ( 2hu·p^{2}·(1/R)·t )^{(1/4)}

Ley: [ de vitamina C psíquica solar ]

(-R)·d_{t}[q] = (1/q(t))^{3}·p^{2}·hu

q(t) = i·( 2hu·(ip)^{2}·(1/R)·t )^{(1/4)}

Ley: [ de vitamina D física solar ]

R·d_{t}[q] = ( q(t) )^{5}·(1/p)^{6}·hu

q(t) = ( 2hu·(1/p)^{6}·(1/R)·t )^{(-1)·(1/4)}

Ley: [ de vitamina D psíquica solar ]

(-R)·d_{t}[q] = ( q(t) )^{5}·(1/p)^{6}·hu

q(t) = i·( 2hu·(1/(ip))^{6}·(1/R)·t )^{(-1)·(1/4)}

Ley: [ de placa solar eléctrica ]

R·d_{t}[q] = (1/q)·hu

q(t) = (1/q)·hu·(1/R)·t

Ley: [ de placa solar gravitatoria ]

(-R)·d_{t}[p] = (1/p)·hu

p(t) = (-1)·(1/p)·hu·(1/R)·t

Ley: [ de placa solar eléctrica ]

R·d_{t}[q] = (1/q)·h·(1/t)

q(t) = (1/q)·h·(1/R)·ln(ut)

Ley: [ de placa solar gravitatoria ]

(-R)·d_{t}[p] = (1/p)·h·(1/t)

p(t) = (-1)·(1/p)·h·(1/R)·ln(ut)

Grabación por calor:

Ley:

R·d_{t}[q] = uT

q(t) = uT·(1/R)·t

Ley:

(-R)·d_{t}[q] = uT

q(t) = (-u)·T·(1/R)·t

Ley:

R·d_{t}[q] = (1/t)·T

q(t) = T·(1/R)·ln(ut)

Ley:

(-R)·d_{t}[q] = (1/t)·T

q(t) = T·(1/R)·ln(1/(ut))

Irodov problems:

Ley:

Sea d[q] = q·(1/r)·d[x] ==>

Si R·d_{t}[q] = uT ==>

x(t) = ruT·(1/R)·(1/q)·t

Ley:

Sea d[q] = q·(1/r)^{n}·nx^{n+(-1)}·d[x] ==>

Si R·d_{t}[q] = uT ==>

x(t) = ( r^{n}·uT·(1/R)·(1/q)·t )^{(1/n)}

Ley:

Sea d[q] = q·(1/x)·d[x] ==>

Si R·d_{t}[q] = uT ==>

x(t) = (1/a)·e^{uT·(1/R)·(1/q)·t}

Ley:

Sea d[q] = q·(1/r)^{n}·u·( nx^{n+(-1)}·d[x]·t+x^{n}·d[t] ) ==>

Si R·d_{t}[q] = uT ==>

x(t) = ( r^{n}·T·(1/R)·(1/q) )^{(1/n)}

Ley:

Sea d[q] = q·(1/r)^{n}·u^{m}·( nx^{n+(-1)}·d[x]·t^{m}+x^{n}·mt^{m+(-1)}·d[t] ) ==>

Si R·d_{t}[q] = uT ==>

x(t) = ( r^{n}·u^{1+(-m)}·T·(1/R)·(1/q)·t^{1+(-m)} )^{(1/n)}

Ley:

Sea d[q] = q·(1/r)^{n}·( nx^{n+(-1)}·d[x]·e^{ut}+x^{n}·ue^{ut}·d[t] ) ==>

Si R·d_{t}[q] = uTe^{ut} ==>

x(t) = ( r^{n}·T·(1/R)·(1/q) )^{(1/n)}

Ley:

Sea d[q] = q·(1/r)^{n}·( nx^{n+(-1)}·d[x]·e^{(m+1)·ut}+x^{n}·(m+1)·ue^{(m+1)·ut}·d[t] ) ==>

Si R·d_{t}[q] = uTe^{ut} ==>

x(t) = ( r^{n}·T·(1/R)·(1/q) )^{(1/n)}·e^{(-1)·(m/n)·ut}

Timoshenko problems:

Ley:

Sea d[ d[q] ] = q·(1/r)·u·h(ut)·d[x]d[t] ==>