martes, 2 de marzo de 2021

lagranianos de puertas tecnología industrial

Lagraniano de puerta de cubo:

E = 2·a_{4}·(x_{4})^{4}

x_{4}(t) = ( 2·(a_{4}/m)^{(1/2)}·t )^{(-1)}

E = (-1)·2·a_{4}·(x_{4})^{4}

x_{4}(t) = ( 2·(a_{4}/m)^{(1/2)}·it )^{(-1)}

E = 2·ia_{4}·(x_{4})^{4}

x_{4}(t) = ( 2·(a_{4}/m)^{(1/2)}·jt )^{(-1)}

E = (-1)·2·ia_{4}·(x_{4})^{4}

x_{4}(t) = ( 2·(a_{4}/m)^{(1/2)}·kt )^{(-1)}


Lagraniano de puerta giratoria de cubo diagonal:

E = (16/5)·a_{5}·(x_{5})^{5}

x_{5}(t) = ( (72/5)^{(1/2)}·(a_{5}/m)^{(1/2)}·t )^{((-2)/3)}

E = (-1)·(16/5)·a_{5}·(x_{5})^{5}

x_{5}(t) = ( (72/5)^{(1/2)}·(a_{5}/m)^{(1/2)}·it )^{((-2)/3)}

E = (16/5)·ia_{5}·(x_{5})^{5}

x_{5}(t) = ( (72/5)^{(1/2)}·(a_{5}/m)^{(1/2)}·jt )^{((-2)/3)}

E = (-1)·(16/5)·ia_{5}·(x_{5})^{5}

x_{5}(t) = ( (72/5)^{(1/2)}·(a_{5}/m)^{(1/2)}·kt )^{((-2)/3)}

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