b = a^{3}+3·ax·(a+x)+x^{3}
2 > 1+3·(2/10)·(1.2)+(8/1000)+s_{1} & 2^{(1/3)} = 1.2
2 > 1.728
2 > (1.728)+3·(1.2)·(5/100)·(1.25)+(125/1000000)+s_{2} & 2^{(1/3)} = 1.25
2 > 1.953125
2 > (1.953125)+3·(1.25)·(9/1000)·(1.259)+(729/1000000000)+s_{3} & 2^{(1/3)} = 1.259
2 > 1.995616979
2.000000 | 1
1.000000 | 3·1·(0.2)·(1.2)+(0.008) = (0.728)
0.272000 | 3·(1.2)·(0.05)·(1.25)+(0.000125) = (0.225125)
0.046875 | 3·(1.25)·(0.009)·(1.259)+(0.000000729) = (0.042491979)
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