2x =[2]= n <==> 2x = 2k+n <==> x = k+(n+(-p))[+]p
2x =[2]= 7 <==> 2x = 2k+7 <==> x = k+6[+]1 = k+5[+]2 = k+4[+]3
4x =[4]= 2n <==> 4x = 4k+2n <==> x = k+(n+(-q))[+](n+(-p))[+]q[+]p
4x =[4]= 14 <==> 4x = 4k+14 <==> ...
... x = k+5[+]6[+]2[+]1 = k+4[+]6[+]3[+]1 = k+4[+]5[+]3[+]2
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