successions monotonia

Si ( a_{n} >] 0 & e^{a_{n}} [< a_{n+1} ) ==> a_{n} és creishent


a_{n} [< 1+a_{n} [< e^{a_{n}} [< a_{n+1}


Si ( a_{n} >] 0 & (-1)·e^{a_{n}} >] a_{n+1} ) ==> a_{n} és decreishent


a_{n} >] (-1)+a_{n} >] (-1)·e^{a_{n}} >] a_{n+1}