lunes, 13 de septiembre de 2021

mecánica relativista

mc^{2}·( 1/( 1+(-1)·( d_{t}[x]/c )^{2} )^{(1/2)} ) = qgx

mc^{2}·( 1/( 1+(-1)·( d_{t}[y]/c )^{2} )^{(1/2)} ) = (-1)·qgy

d_{t}[x(t)] = c·cos( g(t) )

d_{t}[y(t)] = c·sin( h(t) )

mc = qg·( sin(g(t)) /o(t)o/ g(t) )·sin(g(t))

mc = (-1)·qg·( cos(h(t)) /o(t)o/ h(t) )·cos(h(t))

g(t) = (1/2)·( (qg)/(mc) )·t

h(t) = (-1)·(1/2)·( (qg)/(mc) )·t

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