teoria de jocs: joc peó 3-2

n=5k:
Si ( a = 1r  &  b = 2n ) ==> ( F=a & V=b )
Si ( a = 2n  &  b = 1r ) ==> ( V=a & F=b )


[a_{0}][00][a_{1}][b_{2}][a_{2}][00][a_{3}][00][00][b_{0}]
[a_{0}][00][a_{1}][b_{2}][a_{2}][00][b_{3}][00][00][b_{0}]


9+((-2)+(-3))+((-2)+(-3))+((-2)+3) = 0
9+((-3)+(-2))+((-3)+(-2))+(3+(-2)) = 0


n=5k+1:
Si ( a = 1r  &  b = 2n ) ==> ( F=a & V=b )
Si ( a = 2n  &  b = 1r ) ==> ( V=a & F=b )


[a_{0}][00][a_{1}][00][a_{2}][00][00][b_{1}][00][00][b_{0}]
[a_{0}][00][a_{1}][00][b_{2}][00][00][b_{1}][00][00][b_{0}]


10+((-2)+(-3))+((-2)+(-3)) = 0
10+((-3)+(-2))+((-3)+(-2)) = 0