hidrocarburo nitrogenado

[∀n][ n >] 2 ] ==>


C_{n}H_{2n+2} + (n+(-1))·N_{2} + e^{+} ==> C_{n}N_{2n+(-2)}H_{2n+2}


C_{n}N_{2n+(-2)}H_{2n+2} + e^{-} ==> C_{n}H_{2n+2} + (n+(-1))·N_{2}


Entalpia de reacción:
[ C_{n}H_{2n+2} ] = 4n
[ (n+(-1))·N_{2} ] = 6n+(-6)


[ C_{n}N_{2n+(-2)}H_{2n+2} ] = 10n+(-6)


4n+(6n+(-6)) = 10n+(-6) = 10n+(-6)