lim[s-->1][ 2·∮ [ z = se^{ix}+a ]-[ (z+a)·(z+(-a)) ] d[z] ] = (-1)·(4/3)·i
lim[s-->1][ 2·∮ [ z = se^{ix}+(-a) ]-[ (z+a)·(z+(-a)) ] d[z] ] = (-1)·(4/3)·i
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