viernes, 10 de enero de 2020

suma directa y números

3 = x^{2}+y^{2}
3 = (1/2)·( x[+]y )^{2}
6 = ( x[+]y )^{2}
6^{(1/2)} = x[+]y


x = ( 6^{(1/2)}/2 )
y = ( 6^{(1/2)}/2 )


5 = x^{2}+y^{2}
5 = (1/2)·( x[+]y )^{2}
10 = ( x[+]y )^{2}
10^{(1/2)} = x[+]y


x = ( 10^{(1/2)}/2 )
y = ( 10^{(1/2)}/2 )


2 = x^{2}+y^{2}
2 = (1/2)·( x[+]y )^{2}
4 = ( x[+]y )^{2}
4^{(1/2)} = x[+]y
2 = x[+]y


x = 1
y = 1

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